Using only a simple calculator, find the values of k such that det(M)=0, where M=⎣4 k 0 1 1 k 1 11⎤. As your answer, enter the SUM of the value(s) of k that satisfy this condition.

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A: M=-4K011K11-8detM=-4-8-K-K-8-K          =32+4K+8K+K2          =K2+4K+8K+32          =K+4K+8

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