using System; class Program { public static void Main(string[] args) { int number = 1; while (number <= 1000) { Console.WriteLine(number); number = number + 1; } } }
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using System;
class
{
public static void Main(string[] args)
{
int number = 1;
while (number <= 1000)
{
Console.WriteLine(number);
number = number + 1;
}
}
}
How would I make this program that counts to 1000 add up all of the numbers?
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- class Output{public static void main(String args[]){Integer i = new Integer(557);float x = i.floatValue();System.out.print(x);}} What will the given code prints on the output screen.class Output{public static void main(String args[]){int x = 3.14;int y = (int) Math.abs(x);System.out.print(y);}} The output of the above Java code is ?using System;class Program{ public static void Main(string[] args) { int number = 1; while (number <= 1000) { Console.WriteLine(number); number = number + 1; } }} Hi, this program is written for C# to count from 1-1000. How would this program be written to print 1000 random numbers instead of counting from 1-1000?
- using System;class Program{ public static void Main(string[] args) { int number = 1; while (number <= 1000) { Console.WriteLine(number); number = number + 1; } }} This code is written in C# to count from 1-1000. How can it be re-written to get numbers from the user until the user enters zero, and then print out the largest of all those numbers?public class Main { public static void main(String[] args) { System.out.println("Your factorial is: " + factorial(9)); }} public static int factorial(int number) { if (number == 0) { return 1; } return number * factorial(number -1); } i need help fixing this code involving recursionusing System;class Program{ public static void Main(string[] args) { int number = 1; while (number <= 1000) { Console.WriteLine(number); number = number + 1; } }} this code is written in C# to count from 1-1000. how can more code be added to this to add up every single number from 1-1000?
- class Output{public static void main(String args[]){byte a[] = { 65, 66, 67, 68, 69, 70 };byte b[] = { 71, 72, 73, 74, 75, 76 };System.arraycopy(a , 0, b, 0, a.length);System.out.print(new String(a) + " " + new String(b));}} The output of the above Java code is ?PROBLEM STATEMENT: Return the factorial of the provided integer parameter. public class FactorialComputation{public static int solution(int n){// ↓↓↓↓ your code goes here ↓↓↓↓return 0;} Can you please help me with the question above the Language is Java and can yiu use the java code that i gave above to answer the questionGetting a error message and I dont understand why public class DebugTwo2 { public static void main(String args[]) { { int a, b; a = 7; b = 4; System.out.println("The sum is " + (a + b); System.out.println("The difference is " + (a - b); System.out.println("The product is " + (a * b); }
- using System;class Program{ public static void Main(string[] args) { int number = 1; while (number <= 500) { Console.WriteLine(number); number = number + 1; } }} how would you add the phrase "I found 275!" into this code when it reaches that number?using System;class Program{ public static void Main(string[] args) { int number = 1; while (number <= 1000) { Console.WriteLine(number); number = number + 1; } }} how can this code be fixed to count from 1-20 and then 50-70 and then from 800-1000?PROBLEM STATEMENT: Return a number divided by 2. public class DivideByTwo{public static double solution(int x){// ↓↓↓↓ your code goes here ↓↓↓↓return 0;}} Can you help me with this question the Laungage is JAVA