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Using the substitution 6 sin(u) = x, we obtain [²√36 - w²dx = [ K sin" u cos” udu where the constants K = m and n = Using this result and your knowledge about indefinite integrals of powers of sin u and cos u. find the indefinite in [x² √36- /36 = x²dx=+C Note: Your answer should be in terms of x, not u.

Using the substitution 6 sin(u) = x, we obtain [²√36 - w²dx = [ K sin" u cos” udu where the constants K = m and n = Using this result and your knowledge about indefinite integrals of powers of sin u and cos u. find the indefinite in [x² √36- /36 = x²dx=+C Note: Your answer should be in terms of x, not u.

Intermediate Algebra
Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Conic Sections
Section8.2: More Parabolas And Some Circles
Problem 63.1PS
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Using the substitution 6 sin(u) = x, we obtain [²√36 - x²dx = [ K sin" u cos" udu where the constants K = m and n = Using this result and your knowledge about indefinite integrals of powers of sin u and cos u. find the indefinite integral | x² √/36 = x²dx = +0 Note: Your answer should be in terms of x, not u.
Transcribed Image Text:Using the substitution 6 sin(u) = x, we obtain [²√36 - x²dx = [ K sin" u cos" udu where the constants K = m and n = Using this result and your knowledge about indefinite integrals of powers of sin u and cos u. find the indefinite integral | x² √/36 = x²dx = +0 Note: Your answer should be in terms of x, not u.
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