Using trigonometric substitution to evaluate: The first thing we'll need to do here is complete the square on the polynomial to get this into a form we can use a trig substitution on. 1 =dx √9x²-36x+37 O 9(x-2)^2+1 49 - (x + 3)^2 2(x - 1)^2-9 O None of the choces

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Q: 9. (a) This is true. (b) This is false. 5 dx = 5x + C

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Q: (y² +1)dx +(2xy+1)dy

A: (y2+1)dx+(2xy+1)dy=0  It is of the form Mdx+Ndy=0whereM=y2+1N=2xy+1Then ∂M∂y=2y       ∂N∂x=2ysince…