Using trigonometric substitution to solve: secx (A) +C 8 csc 2x√3+cos²x sin 2x B 8 cos x√3-cos²x sin 2x 4 cos x√4-sin²x 8 sec x√4-sin²x D +C + C + C cos x dx (4-sin²x)ž
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- INTEGRAL OF TRIGONOMETRIC FUNCTION Put your clear solution ∫sin8x cos15x dx Choices: A.) -1/23 cos23x + 1/7 cos7x + C B.) [-1/2 cos23x + 1/7 cos7x ] + C C.) 1/2 [-1/23 cos23x + 1/7 cos7x ] + C D.) None of the choicesTrig Method. Rewrite as f ( 1 - sin 2 x) cos2 x sin x dx. Then use u-substitution with u = cos x and du = - sin x dx.sin 2x + sin x + cos 2x - 1 = _______ cos x cot x tan x sin x
- Using reciprocal identities how do you solve this problem? is it solvable? Cosx - Secx = -SinxTanxINTEGRAL OF TRIGONOMETRIC FUNCTION Put your clear solution ∫((cos^5 2x)/(sin^3 2x))dx Choices: A.) 1/4 (csc^2 (2x) - 4 ln|sin2x | + sin〗^2 (2x) ) + C B.) 1/4 (-csc^2 (2x) + 4 ln|sin2x |+ sin^2 (2x) + C C.) 1/4 (-csc^2 (2x) - 4 ln|sin2x | - sin^2 (2x) + C D.) None of the choicessin(x)=−0.2cos(y)=0.4tan(z)=5.5 sin(−x)= 0.2cos(−y)= 0.4tan(−z)= -5.5 What does sec(−y)csc(−x)cot(−z)sin(−x) equal?