ute the derivative of the given function in two different ways.   h(s)=(−9s+9)(−2s+4)h(s)=(−9s+9)(−2s+4) a) Use the Product Rule, [fg]′=f⋅g′+f′⋅g[fg]′=f⋅g′+f′⋅g. (Fill in each blank, then simplify.) h′(s)=(h′(s)=(__ )⋅(__)⋅(__)+(___)+(___  )⋅(__)⋅(___)= __. b) Use algebra first to simplify hh, then differentiate without the Product Rule. h′(s)= ___

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