Answered: V: 818 mV V(p-p): 0 V V(rms): 0 V…

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Electrical Engineering

V: 818 mV V(p-p): 0 V V(rms): 0 V V(dc): 818 mv V(freq): -- R1 A PR1 4.7kQ R2 36.8kQ: R3 10KQ V1 10V · V2 15V

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.1MCQ: The rms value of v(t)=Vmaxcos(t+) is given by a. Vmax b. Vmax/2 c. 2Vmax d. 2Vmax

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Concept explainers

Power Measurement

According to Blondel's theorem, the total power is measured with one less number of wattmeters than the number of wires present in the system. So, a single-phase and two-wire system will require one wattmeter and a single-phase and the three-wire system will require two wattmeters, and a three-phase and the three-wire system will also require two wattmeters and a three-phase and the four-wire system will require three wattmeter devices. The wattmeter is a device that measures power using one voltage and one current input as shown in the above figure. Multiple current or voltage input pair cables are used by many power analyzers and digital storage oscilloscopes (DSOs) for measuring watts, in effect within a single instrument acting as multiple wattmeters. It is possible to measure three-phase and four-wire power with one correctly specified power analyzer.

Question

How to get 818mV in manual solving

V: 818 mv
V(p-p): 0 V
V(rms): 0 V
V(dc): 818 mv
V(freq): --
R1
A
PR1
:4.7KQ
R2
6.8kQ:
R3
10KQ
V1
-10V
V2
-15V

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