V29. Verify that the piecewise-defined function (-, x<0 y = 2, x 0 is a solution of the differential equation xy'- 2y = 0 on (-00, 00),

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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ASHIFT
ALT
FN
CTRL
13
1.1 DEFINITIONS AND TERMINOLOGY
V29. Verify that the piecewise-defined function
-x, x<0
y 3=
2, x20
is a solution of the differential equation xy'- 2y 0 on
(-00, 00).
1(x) = V25 -x and
is an 30. In Example 7 we saw that y =
- Pro-
d give
y = 2(x) = -V25 -x are solutions of dy/dx = -x/y on the
interval (-5, 5). Explain why the piecewise-defined function
D.E
oge.
rential
ĮV25 -
1-V25 - ,
-5<x<0
y =
0Sx<5
Transcribed Image Text:ASHIFT ALT FN CTRL 13 1.1 DEFINITIONS AND TERMINOLOGY V29. Verify that the piecewise-defined function -x, x<0 y 3= 2, x20 is a solution of the differential equation xy'- 2y 0 on (-00, 00). 1(x) = V25 -x and is an 30. In Example 7 we saw that y = - Pro- d give y = 2(x) = -V25 -x are solutions of dy/dx = -x/y on the interval (-5, 5). Explain why the piecewise-defined function D.E oge. rential ĮV25 - 1-V25 - , -5<x<0 y = 0Sx<5
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