V9x² – 5 - dx . .2 fact to determine the integral 9x?

Q: Evaluate the integral 3. 2х dx х2 — 4

A: Will use substitution to find this integral. Substitute x square - 4 is equal to t.

Q: Find the indefinite integral. Vx +2 -dp- 3 X,

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Q: Evaluate the integral. X-7 dx X-7 dx = 8 %3D

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Q: 2x Use substitution to evaluate the integral dx (x² + 3)°

A: We have to apply rules of integration to solve the problem Power rule: xn =( 1/n+1)(x)n-1

Q: 1 + 10/x| dx 3x3

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Q: Evaluate the integral | 3 dx. V9x -4

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Q: +1 dx. (x+3:2-5)3

A: To evaluate  ∫x2+1x3+3x-53dx

Q: Evaluate the integral. 3* dx V3* + 4

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Q: Evaluate the integrals

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Q: Evaluate the integral. dx =, x>6 x - 36 dx x²x - 36

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Q: Evaluate the integral. бх + 2 dx = | x2 + 2x – 3 -

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Q: Use u-substitution to evaluate the integral: x/(x+2)^3   dx

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Q: Evaluate the integral. '5 dx (x2 - 1)3/2

A: *Given integral is, I=∫251x2-132dx Integrate the above expression. I=∫251x2-132dx Put,…

Q: Evaluate the integral.

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Q: Find the indefinite integral.

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Q: Evaluate the integral ∫ dx / 3−2sinx.

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Q: Evaluate the integral

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Q: 3 3+ Vx dx

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Q: Use any method to evaluate the integral. 8 dx (16x? + 1)?

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Q: [(7x-2)e-* dx; -3x

A: The given question can be solved as shown in step2.

Q: Evaluate the integral. х3 — 5х — 8 dx x2 — х — 6 -

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Q: Evaluate the integral. -2. 3 17 secx tanx dx

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Q: Evaluate the integral: x(19 – x)3/2 dx = %3D

A: Given: ∫x(19-x)32dx

Q: Evaluate the integral. 1/6 dx = 5x J1/13

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Q: dx 4 3

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Q: Evaluate the integral. 0.4 x2 dx 4 - 25x2 |

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Q: Find the integral

A: Given:              ∫x8-x32dx apply u-substitution: u=8-x⇒du=-dx           =∫--u+8u32du take the…

Q: Evaluate the integral. [HINT: Use a shortcut.] 2 2-x + 1 dx

A: The integral is  ∫022-x+1dx

Q: Use substitution to find the indefinite integral.

A: Given integral: ∫x2-6xx-3 dx Substitute u=x2-6x and differentiate it w.r.t 'x'…

Q: Evaluate the integral. 3 dx -2

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Q: Use substitution to find the general integral (x-4) *dx x²(x- 4) $dx = %3D |

A: We have to find the integral

Q: dx ,2 /9 – x² 2

A: Solution

Q: Evaluate the integral. 0. (4.4x2 - 1) dx

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Q: Evaluate the integral. '5 x - 4 dx x2 - 3x - 18

A: We first factor the denominator. ∫-25x-4x2-3x-18dx=∫-25x-4(x-6)(x+3)dx

Q: 2. Use reduction formula to evaluate the integral: fsins x dx.

A: Reduction formula

Q: Evaluate the integral. 1/3 -1 dx = | 0.423 2x %3D /1/7

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Q: Evaluate the integral. (x3 – 6x)dx -2

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Q: evaluate the defmite Integral га (X -2)dx 4.

A: Given integral:

Q: Evaluate the integral dx 2xx - 3x?

A: To find: The integral ∫dx 2xx3-3x23 Concept used: ∫1-v2+1dv=lnv+12-lnv-12

Q: Evaluate the integral.

A: It is given that, ∫021x+33dxWe have to evaluate it.

Q: 1 dx Vx-2

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Q: Evaluate the integral (2х — 8)dx - x2 – 6x + 18

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Q: find the inderinite integral it 2. dx 7-3x3

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Q: Evaluate the integral (2х + 6)dx х2 — 2х + 17

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Q: Evaluate the integral. 8. dx (x² – 1)3/2

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Q: Evaluate the integral

A: Given: ∫00.6x29-25x2dx

Q: Fine the integral of sec ^4x tan ^3x dx

A: We  will  solve  the integral. We know, (1) tanθ = sinθ/ cosθ                (2)  Secθ= 1/ cosθ…

Q: Sx (x² + 4)5 Se3*dx

A: