Verify that λ, is an eigenvalue 8 -1 3 0 6 1 07 0 Ax₁ = Ax₂ = A 8-1 3 0 61 0 0 07 0 8-13 0 0 6 1 2 07 81 3 Ax₂ = 0 of A and that x; is a corresponding eigenvector. A₁ = 8, x₁ = (1, 0, 0) ₂ = 6₁ x₂ = (1, 2, 0) A3 = 7, x₂ = (-2, 1, 1) 61 07 ↓ T 000= 4E0 ↓ 1 ---- = 80=2₁x₁ [] 2 =2₂x₂ 7 [1]] = λ₂x3
Verify that λ, is an eigenvalue 8 -1 3 0 6 1 07 0 Ax₁ = Ax₂ = A 8-1 3 0 61 0 0 07 0 8-13 0 0 6 1 2 07 81 3 Ax₂ = 0 of A and that x; is a corresponding eigenvector. A₁ = 8, x₁ = (1, 0, 0) ₂ = 6₁ x₂ = (1, 2, 0) A3 = 7, x₂ = (-2, 1, 1) 61 07 ↓ T 000= 4E0 ↓ 1 ---- = 80=2₁x₁ [] 2 =2₂x₂ 7 [1]] = λ₂x3
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter4: Eigenvalues And Eigenvectors
Section4.1: Introduction To Eigenvalues And Eigenvectors
Problem 4EQ: In Exercises 1-6, show that vis an eigenvector of A and find the corresponding eigenvalue....
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