Verify the identity. sin-1 x + sin-1(-x) = 0 Let a = sin-1 x and 8 = sin-1(-x). These equations imply the following. sin a = x sin B -x Looking at the right triangles for these values, the following is true. cos a = V1-? cos B = V1-? Making these substitutions, we see that sin-1 x + sin-1(-x) = a + B sin-1 sin(a + B) sin-(sin a cos B + cos(a) sin(B) - sin-1. (xv1 - x² + V1-x (-x) = sin-1.0

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 5E
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q.23 , 3.5 (new) PLEASE ENTER THE ANSWER EXACTLY AS STATED IN THE BOX I JUST NEED THE EXACT ANSWER FOR THE ONE WITH THE RED X BY IT PLEASE PLEASE! EXACTLY AS IT SAYS IN THE BOX WITH THE RED X PLEASE

 

Verify the identity.
sin-1 x + sin-1(-x)
= 0
Let a = sin-1 x and 8 = sin-1(-x). These equations imply the following.
sin a = x
sin B
-x
Looking at the right triangles for these values, the following is true.
cos a = V1-?
cos B = V1-?
Making these substitutions, we see that
sin-1 x + sin-1(-x) = a + B
sin-1 sin(a + B)
sin-(sin a cos B + cos(a) sin(B)
- sin-1. (xv1 - x² +
V1-x (-x)
= sin-1.0
Transcribed Image Text:Verify the identity. sin-1 x + sin-1(-x) = 0 Let a = sin-1 x and 8 = sin-1(-x). These equations imply the following. sin a = x sin B -x Looking at the right triangles for these values, the following is true. cos a = V1-? cos B = V1-? Making these substitutions, we see that sin-1 x + sin-1(-x) = a + B sin-1 sin(a + B) sin-(sin a cos B + cos(a) sin(B) - sin-1. (xv1 - x² + V1-x (-x) = sin-1.0
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