Verify the theorem of total expectation (TTE).

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter4: Calculating The Derivative
Section4.4: Derivatives Of Exponential Functions
Problem 53E
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(9) When X, Y have a bivariate normal density with respective means µx, µy, respective variables o7, o7 and correlation p, we have
E(X|Y = y) = Hx+
ρσχ
(y – HY),
Var(X|Y = y) = o(1 – p²).
σΥ
Verify the theorem of total expectation (TTE).
The following verifications are proposed.
(a) Since Var(X|Y = y) = ož(1 - p²) does not depend on y, therefore, the TTE holds.
(b) Since E(X|Y = y) depends only on y, the TTE holds.
(c) Since E(X|Y) = µx +
Pox
* (Y – µy), we see that E(E(X|Y)) = µx = E(X). Therefore, the TTE holds.
(d) TTE does not hold.
(e) None of the above
The correct verification is
(a)
(b)
(c)
(d)
(e)
N/A
(Select One)
Transcribed Image Text:(9) When X, Y have a bivariate normal density with respective means µx, µy, respective variables o7, o7 and correlation p, we have E(X|Y = y) = Hx+ ρσχ (y – HY), Var(X|Y = y) = o(1 – p²). σΥ Verify the theorem of total expectation (TTE). The following verifications are proposed. (a) Since Var(X|Y = y) = ož(1 - p²) does not depend on y, therefore, the TTE holds. (b) Since E(X|Y = y) depends only on y, the TTE holds. (c) Since E(X|Y) = µx + Pox * (Y – µy), we see that E(E(X|Y)) = µx = E(X). Therefore, the TTE holds. (d) TTE does not hold. (e) None of the above The correct verification is (a) (b) (c) (d) (e) N/A (Select One)
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