VGS = 2.30 V VIO +2.5 V M₁ VDS = 2.30 V V SB + -0%= V₁ = 0.20 V + UDS = 0.20 V Ms
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- balanced load is connected in star across a 3 phasec415V 50Hz supply. The load consists of a coil of resistance 25 ohms and inducrance 0.5 henry in paeallel with a purw resistance of 28 ohms and a pure capaciror of 60microfarads capacitance ,in each branch. Calculate a. The line currents The answer 9.3A need full working pleaseNeed asap pls help. Solve for the voltages across and currents through each component. Show the complete solution and explain. The total power should be zero.A 240V, 60 Hz source is suppling power the following: Load 1: 10kVA @ pf = 0.55 lagging Load 2: 5kVA @ pf = 1 Load 3: 3kVAR @ pf = 0.60 leading Calulcate the following
- For the figure 2 below, how do I find: Total impedence ZT The voltage V1 in phasor form The current I1 in phasor form The voltage V2 in phasor form & the source voltage Vs in phasor formDetermine vs , vy and io if Vz =8V and R1=60ohm and R2=70ohm9. What is the maximum power if the impedance draws a current of i= 10cos(wt-30o ) from a voltage equation of v = 220sinwt?
- In a phasor domain circuit, 220L30° V is applied across two series components, one ofwhich is a 20 Ω resistor and the other of which is a coil with an impedance of 40L20° Ω.Use current to find the individual component voltage drop.The circuit of the Figure below has Z1= 5 angle 0 , Z2= 9 angle 30 and Z3= 10 angle 80, and is supplied by a 3-phase 450-V solve for IaThe answer must be 110.29 angle -36.52The actual impedance of a system is 300 Ω. The base kVA is 300 kVA, and the base voltage is 11 kV. What is the actual impedance with 400 kVA and 38 kV as base values? a. 300 b. 33.52 c. 0.744 d. 0.083
- IR = = 8mA∠0° IL = 12.732mA∠-90° Is(p-p) = 15.04mA∠-57.86° I got the currents, can you help me im finding VR and VL pleaseHelp Please A series circuit has R = 100 ohm L = 50mH and C = 100μF and is supplied with 200V,50Hz. Find (i) Impedance (ii) Current and voltage drop across the each element (iii) power and power factorDetermine the impedance value of the three "loads" and VL in the following circuit if the source voltage V(t) = 30 · sin(377 · t + 45° ) volts R=20Ω L=50mH C=100uF