USE 2 decimal places, rio commas.Given:Voltage-divider biased, npn BJT with1. VCC = 22V2. R139kohms3. R2 7kohms4. RC= 4kohms5. RE 1 kohms 6. BDC = 149**Solve for:1. VB Blank 1 V.2. VE Blank 2 V;3. IE= Blank 3 mA;4. VCE Blank 4 V;5. VC Blank USE APPROXIMATE ANALYSISUSE 2 decimal places, no commas.Given:Voltage-divider biased, npn BJT with1. VCC = 22V2. R1 = 39kohms3. R2 = 7kohms4. RC = 4kohms5. RE = 1kohms6. BDC = 149Solve for1. VB = Blank 1 V,2. VE = Blank 2 V;3.IE = Blank 3 mA;4. VCE = Blank 4 V;5. VC = Blank 5 VBlank 1Add your answerBlank 2

Answered: Image /qna-images/answer/502826b0-f575-4c4d-9927-22d5d728c6d4.jpg

Voltage-divider biased, npn BJT with 1. VCC = 22V 2. R1 = 39kohms %3D 3. R2 = 7kohms 4. RC = 4kohms %3D 5. RE = 1kohms %3D 6. BDC = 149 %3D Solve for: 1. VB = Blank 1 V; 2. VE = Blank 2 V; 3. IE = Blank 3 mA; %3D 4. VCE = Blank 4 V; %3D 5. VC = Blank 5 V:

Voltage-divider biased, npn BJT with 1. VCC = 22V 2. R1 = 39kohms %3D 3. R2 = 7kohms 4. RC = 4kohms %3D 5. RE = 1kohms %3D 6. BDC = 149 %3D Solve for: 1. VB = Blank 1 V; 2. VE = Blank 2 V; 3. IE = Blank 3 mA; %3D 4. VCE = Blank 4 V; %3D 5. VC = Blank 5 V:

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.30P: Reconsider Problem 3.29. If Va,VbandVc are a negative-sequence set, how would the voltage and...

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Question

USE 2 decimal places, rio commas. Given: Voltage-divider biased, npn BJT with 1. VCC = 22V 2. R139kohms 3. R2 7kohms 4. RC= 4kohms 5. RE 1 kohms 6. BDC = 149 ** Solve for: 1. VB Blank 1 V. 2. VE Blank 2 V; 3. IE= Blank 3 mA; 4. VCE Blank 4 V; 5. VC Blank

USE APPROXIMATE ANALYSIS
USE 2 decimal places, no commas.
Given:
Voltage-divider biased, npn BJT with
1. VCC = 22V
2. R1 = 39kohms
3. R2 = 7kohms
4. RC = 4kohms
5. RE = 1kohms
6. BDC = 149
Solve for
1. VB = Blank 1 V,
2. VE = Blank 2 V;
3.IE = Blank 3 mA;
4. VCE = Blank 4 V;
5. VC = Blank 5 V
Blank 1
Add your answer
Blank 2

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