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What is the derivative of the following function?
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- how to find the bounds of y=sin(x) y=cos(x) x=0Find the first derivative of y = (x – 1) √ (2x – x2) + arcsin (x – 1), and y = arctan [ (3 sin x) / (4 + 5 cos x) ], and y = ( ex – e –x ) / (ex + e –x ) Simplify the answer but make the solution detailed and clear.Prove the identities sinh (x + y) = sinh x cosh y + cosh x sinh y, cosh (x + y) = cosh x cosh y + sinh x sinh y. Then use them to show that a. sinh 2x = 2 sinh x cosh x. b. cosh 2x = cosh2x + sinh2 x.