Vx3 – 12x2 is achieves its absolute On the interval[-2,3], function f(x) = x – (global) minimum at At a point x where f'(x) = 0 (i.e. a critical point) x = 3. At a point x where f'(x) does not exist (i.e. a singular point). Ox = -2. At a point x where f is discontinuous.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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On the interval [-2, 3], function f(x) = x -
(global) minimum at
Vx3 – 12x2 is achieves its absolute
O At a point x where f ' (x) = 0 (i.e. a critical point)
x = 3.
At a point x where f' (x) does not exist (i.e. a singular point).
Ox = -2.
At a point x where f is discontinuous.
Transcribed Image Text:On the interval [-2, 3], function f(x) = x - (global) minimum at Vx3 – 12x2 is achieves its absolute O At a point x where f ' (x) = 0 (i.e. a critical point) x = 3. At a point x where f' (x) does not exist (i.e. a singular point). Ox = -2. At a point x where f is discontinuous.
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