Vy: y(0) = 1 dx dy Vy: y(0) = 0 %3D %3D dx dy - x-y; y(2) = 2 %3D dx dy VX-y; y(2) = 1 %3D dx

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Do 17, and use Theorem 1 existence and uniqueness of solutions of section: slope fields and soluton curves.

A more detailed version of Theorem 1 says that, if the function
f (x, y) is continuous near the point (a, b), then at least one so-
lution of the differential equation y' f(x, y) exists on some
open interval I containing the point x a and, moreover, that
if in addition the partial derivative af/ay is continuous near
(a,b), then this solution is unique on some (perhaps smaller)
interval J. In Problems 11 through 20, determine whether ex-
istence of at least one solution of the given initial value prob-
lem is thereby guaranteed and, if so, whether uniqueness of
that solution is guaranteed.
%3D
dy
11.
dx
2x2 y2; y(1) = -1
dy
12.
x In y;
dx
y(1) = 1
13.
dx
dy
= Vy; y(0) = 1
14.
dx
dy
Vy: y(0) = 0
dy
15.
VX- y; y(2) = 2
dx
dy
16.
dx
X- y; y(2) = 1
dy
17. y
=x-1; y(0) = 1
dx
18.
=x-1: y(1) =0
dx
dy
- In(1
2
19.
Transcribed Image Text:A more detailed version of Theorem 1 says that, if the function f (x, y) is continuous near the point (a, b), then at least one so- lution of the differential equation y' f(x, y) exists on some open interval I containing the point x a and, moreover, that if in addition the partial derivative af/ay is continuous near (a,b), then this solution is unique on some (perhaps smaller) interval J. In Problems 11 through 20, determine whether ex- istence of at least one solution of the given initial value prob- lem is thereby guaranteed and, if so, whether uniqueness of that solution is guaranteed. %3D dy 11. dx 2x2 y2; y(1) = -1 dy 12. x In y; dx y(1) = 1 13. dx dy = Vy; y(0) = 1 14. dx dy Vy: y(0) = 0 dy 15. VX- y; y(2) = 2 dx dy 16. dx X- y; y(2) = 1 dy 17. y =x-1; y(0) = 1 dx 18. =x-1: y(1) =0 dx dy - In(1 2 19.
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