W.5: Determine i, io, and v, for all t in the circuit shown in Fig.. Assume that the vitch was closed for a long time. It should be noted that opening a switch in series with ideal current source creates an infinite voltage at the current source terminals. Clearly is is impossible. For the purposes of problem solving, we can place a shunt resistor in rallel with the source (which now makes it a voltage source in series with a resistor). In pre practical circuits, devices that act like current sources are, for the most part, ectronic circuits. These circuits will allow the source to act like an ideal current source er its operating range but voltage-limit it when the load resistor becomes too large (as in open circuit). (12A t<0 t<0 (6A -4e-2tA t>0' nswer: i = {12e-2t A t20' t<0 v, = 8e-2tv t> 0 (24V i. %3D 3Ω ww t= 0 1 H 18 A 4Ω 2Ω ww

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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H.W.5: Determine i, io, and v, for all t in the circuit shown in Fig.. Assume that the
switch was closed for a long time. It should be noted that opening a switch in series with
an ideal current source creates an infinite voltage at the current source terminals. Clearly
this is impossible. For the purposes of problem solving, we can place a shunt resistor in
parallel with the source (which now makes it a voltage source in series with a resistor). In
more practical circuits, devices that act like current sources are, for the most part,
electronic circuits. These circuits will allow the source to act like an ideal current source
over its operating range but voltage-limit it when the load resistor becomes too large (as in
an open circuit).
t<0
(6A
-4e-2t A t> 0
(12A
t<0
(24V
t<0
Answer: i =
(12e-2tA t2 0'
vo
18e-2tv t>0
32
t= 0
1H
ll
18 A
42
2Ω
Transcribed Image Text:H.W.5: Determine i, io, and v, for all t in the circuit shown in Fig.. Assume that the switch was closed for a long time. It should be noted that opening a switch in series with an ideal current source creates an infinite voltage at the current source terminals. Clearly this is impossible. For the purposes of problem solving, we can place a shunt resistor in parallel with the source (which now makes it a voltage source in series with a resistor). In more practical circuits, devices that act like current sources are, for the most part, electronic circuits. These circuits will allow the source to act like an ideal current source over its operating range but voltage-limit it when the load resistor becomes too large (as in an open circuit). t<0 (6A -4e-2t A t> 0 (12A t<0 (24V t<0 Answer: i = (12e-2tA t2 0' vo 18e-2tv t>0 32 t= 0 1H ll 18 A 42 2Ω
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