was equal to the width of one rectangle in feet and 480 − 2x was the length in feet of all three rectangles combined. Area(Three Rectangles) = (Width)(Length) Area(Three Rectangles) = (x)(480 − 2x) Show all work. Use the above equation, expand, simplify and complete the square. From the information you calculate, determine the following: a) The greatest possible area for one of the three rectangles. b) The dimensions of one of the rectangles.
2. Massimo and his friends were given 960 feet of rope in phys. ed class, so that they could
make the boundaries of 3 equal sized rectangles where they would be playing socially distanced
games. The rectangles had to be connected to each other. Mr. Notice drew a quick sketch of
how to arrange the rectangles. It was up to Massimo to calculate the dimensions that would give
the greatest possible area for each rectangle.
Massimo created an equation where x
was equal to the width of one rectangle
in feet and 480 − 2x was the length in feet
of all three rectangles combined.
Area(Three Rectangles) = (Width)(Length)
Area(Three Rectangles) = (x)(480 − 2x)
Show all work. Use the above equation, expand, simplify and complete the square.
From the information you calculate, determine the following:
a) The greatest possible area for one of the three rectangles.
b) The dimensions of one of the rectangles.
Step by step
Solved in 4 steps with 4 images
