Water is discharged from a reservoir into the atmosphere through a pipe 39 m long. There is a sharp entrance to the pipe and the diameter is 50 mm for 15 m from the entrance. The pipe then enlarges suddenly to 75 mm in diameter for the remainder of its length. Taking into account the loss of head at entry and at the enlargement, calculate the difference of level between the surface of the reservoir and the pipe exit which will maintain a flow of 0.0028 m³/s. Take fas 0.0192 for the 50 mm pipe and 0.0232 for the 75 mm pipe. (Notes: Use Darcy Weisbach's equation, h,= (flv²)/(2dg). Q=0.0028 m³/s LBC = 15 m dBc = 50 mm JBC=0.0192 LCD = 24 m dcD = 75 mm SCD=0.0232 h ??

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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Water is discharged from a reservoir into the atmosphere through a pipe 39 m long.
There is a sharp entrance to the pipe and the diameter is 50 mm for 15 m from the
entrance. The pipe then enlarges suddenly to 75 mm in diameter for the remainder
of its length. Taking into account the loss of head at entry and at the enlargement,
calculate the difference of level between the surface of the reservoir and the pipe
exit which will maintain a flow of 0.0028 m³/s. Take fas 0.0192 for the 50 mm pipe
and 0.0232 for the 75 mm pipe.
(Notes: Use Darcy Weisbach's equation, h,= (flv²)/(2dg).
Q=0.0028 m³/s
LBC = 15 m
dBc = 50 mm
fBC = 0.0192
LCD = 24 m
dcD = 75 mm
fCD=0.0232
h ??
Transcribed Image Text:Water is discharged from a reservoir into the atmosphere through a pipe 39 m long. There is a sharp entrance to the pipe and the diameter is 50 mm for 15 m from the entrance. The pipe then enlarges suddenly to 75 mm in diameter for the remainder of its length. Taking into account the loss of head at entry and at the enlargement, calculate the difference of level between the surface of the reservoir and the pipe exit which will maintain a flow of 0.0028 m³/s. Take fas 0.0192 for the 50 mm pipe and 0.0232 for the 75 mm pipe. (Notes: Use Darcy Weisbach's equation, h,= (flv²)/(2dg). Q=0.0028 m³/s LBC = 15 m dBc = 50 mm fBC = 0.0192 LCD = 24 m dcD = 75 mm fCD=0.0232 h ??
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