Water is flowing through a horizontal 6 in. Schedule 40 mild steel pipe at 1 atm and 25°C. The inside diameter and the length of the pipe are 0.154 m and 1500 m, respectively, and the roughness factor is 0.0000457 m. The inlet and outlet conditions are P₁ = 20 atm, Z₁ = 0 m, P₂ = 2 atm, and Z2 = 100 m. The density of water is 1000 kg/m³ and the viscosity is 0.001 kg/(m-sec). Calculate the inlet volumetric flow rate (m³/sec) and the pressure drop AP = 2fLv2/D (kPa). The friction factor f is given by the Colebrook equation as follows: ε 1.255 1 -1.7372 In + (3.7D NRe√f) Answer: inlet volumetric flowrate = 0.0610367 m³/sec pressure drop due to friction loss = 849.219 kPa

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
icon
Related questions
Question

can someone find a solution to this problem

Water is flowing through a horizontal 6 in. Schedule 40 mild steel pipe at 1 atm and 25°C. The
inside diameter and the length of the pipe are 0.154 m and 1500 m, respectively, and the
roughness factor is 0.0000457 m. The inlet and outlet conditions are P1 = 20 atm, z1 = 0 m, P2 =
2 atm, and z2 = 100 m. The density of water is 1000 kg/m3 and the viscosity is 0.001kg/(m-sec).
Calculate the inlet volumetric flow rate (m³/sec) and the pressure drop APf
%3D
2fLv? /D (kPa).
The friction factor f is given by the Colebrook equation as follows:
1.255
1
-1.7372 In
3.7D NReVf,
Answer:
inlet volumetric flowrate = 0.0610367 m³/sec
pressure drop due to friction loss = 849.219 kPa
Transcribed Image Text:Water is flowing through a horizontal 6 in. Schedule 40 mild steel pipe at 1 atm and 25°C. The inside diameter and the length of the pipe are 0.154 m and 1500 m, respectively, and the roughness factor is 0.0000457 m. The inlet and outlet conditions are P1 = 20 atm, z1 = 0 m, P2 = 2 atm, and z2 = 100 m. The density of water is 1000 kg/m3 and the viscosity is 0.001kg/(m-sec). Calculate the inlet volumetric flow rate (m³/sec) and the pressure drop APf %3D 2fLv? /D (kPa). The friction factor f is given by the Colebrook equation as follows: 1.255 1 -1.7372 In 3.7D NReVf, Answer: inlet volumetric flowrate = 0.0610367 m³/sec pressure drop due to friction loss = 849.219 kPa
Expert Solution
steps

Step by step

Solved in 4 steps with 27 images

Blurred answer
Recommended textbooks for you
Introduction to Chemical Engineering Thermodynami…
Introduction to Chemical Engineering Thermodynami…
Chemical Engineering
ISBN:
9781259696527
Author:
J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:
McGraw-Hill Education
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemical Engineering
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
Elements of Chemical Reaction Engineering (5th Ed…
Elements of Chemical Reaction Engineering (5th Ed…
Chemical Engineering
ISBN:
9780133887518
Author:
H. Scott Fogler
Publisher:
Prentice Hall
Process Dynamics and Control, 4e
Process Dynamics and Control, 4e
Chemical Engineering
ISBN:
9781119285915
Author:
Seborg
Publisher:
WILEY
Industrial Plastics: Theory and Applications
Industrial Plastics: Theory and Applications
Chemical Engineering
ISBN:
9781285061238
Author:
Lokensgard, Erik
Publisher:
Delmar Cengage Learning
Unit Operations of Chemical Engineering
Unit Operations of Chemical Engineering
Chemical Engineering
ISBN:
9780072848236
Author:
Warren McCabe, Julian C. Smith, Peter Harriott
Publisher:
McGraw-Hill Companies, The