Water is poured into the bucket below at a volume rate of 10 cm³/s. Thesurface area of the bucket's bottom, Ao, is given as 10 cm?. What is the rate ofchange for z with respect to time at h=12 cm? The volume of the bucket canbe found by integrating:v = /(Ao + 42) dzVtzhi AoFigure 1: Half cone

Here we have to use Fundamental theorem of calculus Part 1 Let f be a continuous real-valued…

Water is poured into the bucket below at a volume rate of 10 cm³/s. The surface area of the bucket's bottom, Ao, is given as 10 cm². What is the rate of change for z with respect to time at h=12 cm? The volume of the bucket can be found by integrating: v = [(Ao + 4:) dz tz h

Water is poured into the bucket below at a volume rate of 10 cm³/s. The surface area of the bucket's bottom, Ao, is given as 10 cm². What is the rate of change for z with respect to time at h=12 cm? The volume of the bucket can be found by integrating: v = [(Ao + 4:) dz tz h

Trigonometry (MindTap Course List)

10th Edition

ISBN:9781337278461

Author:Ron Larson

Publisher:Ron Larson

Chapter6: Topics In Analytic Geometry

Section: Chapter Questions

Problem 33CT

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Question

Water is poured into the bucket below at a volume rate of 10 cm³/s. The
surface area of the bucket's bottom, Ao, is given as 10 cm?. What is the rate of
change for z with respect to time at h=12 cm? The volume of the bucket can
be found by integrating:
v = /(Ao + 42) dz
V
tz
h
i Ao
Figure 1: Half cone

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