Water (specific gravity, G, is 1.0 and the kinematic viscosity, ν, is 1.14 *10-6 m2 /s) flows through a piping system with a flow rate of 0.9 m3/s. The pipe is 2800 m long and 600 mm inside diameter. The pipe has three gate valves, two globe valves, one swing check valve, three standard tees through-branch, and four 90o standard elbows. Calculate the following: c- The Darcy friction factor if the pipe is fully rough and has an absolute internal roughness, e, of 0.01 mm. d- The frictional head loss in units of (m) using the Darcy equation.
Water (specific gravity, G, is 1.0 and the kinematic viscosity, ν, is 1.14 *10-6 m2 /s) flows through a piping system with a flow rate of 0.9 m3/s. The pipe is 2800 m long and 600 mm inside diameter. The pipe has three gate valves, two globe valves, one swing check valve, three standard tees through-branch, and four 90o standard elbows. Calculate the following: c- The Darcy friction factor if the pipe is fully rough and has an absolute internal roughness, e, of 0.01 mm. d- The frictional head loss in units of (m) using the Darcy equation.
Refrigeration and Air Conditioning Technology (MindTap Course List)
8th Edition
ISBN:9781305578296
Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Chapter1: Heat, Temperature, And Pressure
Section: Chapter Questions
Problem 17RQ: Convert 22C to Fahrenheit.
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Water (specific gravity, G, is 1.0 and the kinematic viscosity, ν, is 1.14 *10-6 m2 /s) flows through a piping system with a flow rate of 0.9 m3/s. The pipe is 2800 m long and 600 mm inside diameter. The pipe has three gate valves, two globe valves, one swing check valve, three standard tees
through-branch, and four 90o standard elbows. Calculate the following:
c- The Darcy friction factor if the pipe is fully rough and has an absolute internal roughness, e, of 0.01 mm.
d- The frictional head loss in units of (m) using the Darcy equation.
Transcribed Image Text:Use the following equations if you need to,
64
f =
Re
2.51
-2 log
Re f
1
1
2.51
e
= -2 log
3.7D
1
-2 log
3.7D, Ref
e
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