We can find (fg)(-2) using the fact that (fg)(-2) = f(-2)· g(-2). f(x) = x² + x f(-2) = (-2)² + (-2) = 4 – 2 = 2 g(x) = x – 5 g(-2) = -2 – 5 = -7 Thus, (fg)(-2) = f(-2) •g(-2) = 2(-7) = -14. We could also have found (fg)(-2) by multiplying f(x) · g(x) and then substituting -2 into the product. We will discuss how to multiply expressions such as x2 + x and x - 5 in Chapter 5. I
We can find (fg)(-2) using the fact that (fg)(-2) = f(-2)· g(-2). f(x) = x² + x f(-2) = (-2)² + (-2) = 4 – 2 = 2 g(x) = x – 5 g(-2) = -2 – 5 = -7 Thus, (fg)(-2) = f(-2) •g(-2) = 2(-7) = -14. We could also have found (fg)(-2) by multiplying f(x) · g(x) and then substituting -2 into the product. We will discuss how to multiply expressions such as x2 + x and x - 5 in Chapter 5. I
ChapterP: Prerequisites
SectionP.4: Factoring Polynomials
Problem 84E: The rate of change of an autocatalytic chemical reaction is kQxkx2 where Q is the amount of the...
Related questions
Question
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps
Recommended textbooks for you
Algebra and Trigonometry (MindTap Course List)
Algebra
ISBN:
9781305071742
Author:
James Stewart, Lothar Redlin, Saleem Watson
Publisher:
Cengage Learning
Algebra and Trigonometry (MindTap Course List)
Algebra
ISBN:
9781305071742
Author:
James Stewart, Lothar Redlin, Saleem Watson
Publisher:
Cengage Learning