i need the answer quickly We have an electrical circuit whose different elements are connected to an alternating current generator of frequencyw, as shown in the figure below.At an instant t, the plates of the capacitor shown (capacitance C) have equal and opposite charges +q(t) and -q(t).and through the coil (self inductance L) passes a known instantaneous current i(t) = l sin (wt + T2).Knowing that the circuit is in its steady state, obtain for time t the electric field as a function of time at each of theclosed surfaces Sa, Sb, and Sc.i(t)+ qlt)S.qlt)i(t)Step by step pleaseWrong|answer gives u downvote

The electric field is a vector quantity that arises from electric charge. It also corresponds to…

We have an electrical circuit whose different elements are connected to an alternating current generator of frequency w, as shown in the figure below Al an instant t, the plates of the capacitor shown (capacitance C) have equal and opposite charges +q(e) and -qe). and through the coil (self inductance L) passes a known instantaneous current i(t) = sin (wt + m2). Knowing that the circuit is in its steady state, obtain for time t the electric field as a function of time at each of the closed surfaces Sa, Sb, and Sc. i(t) + qit) i(t)

We have an electrical circuit whose different elements are connected to an alternating current generator of frequency w, as shown in the figure below Al an instant t, the plates of the capacitor shown (capacitance C) have equal and opposite charges +q(e) and -qe). and through the coil (self inductance L) passes a known instantaneous current i(t) = sin (wt + m2). Knowing that the circuit is in its steady state, obtain for time t the electric field as a function of time at each of the closed surfaces Sa, Sb, and Sc. i(t) + qit) i(t)