We have given a task to subnet the following network 10.80.0.0 with subnet mask 255.240.0.0. a) How many available IP addresses do we have within given address space? b) How many subnets (with a size of 5000 hosts per each) can we create? c) Assign network space for both departments in the following order: Department A: 5000 usable IP addresses. Department B: 10000 usable IP addresses. For each deparment note down Network ID and its corresponding broadcast address

We have given a task to subnet the following network 10.80.0.0 with subnet mask 255.240.0.0. a) How many available IP addresses do we have within given address space? b) How many subnets (with a size of 5000 hosts per each) can we create? c) Assign network space for both departments in the following order: Department A: 5000 usable IP addresses. Department B: 10000 usable IP addresses. For each deparment note down Network ID and its corresponding broadcast address

Comptia A+ Core 1 Exam: Guide To Computing Infrastructure (mindtap Course List)

10th Edition

ISBN:9780357108376

Author:Jean Andrews, Joy Dark, Jill West

Publisher:Jean Andrews, Joy Dark, Jill West

Chapter8: Network Infrastructure And Troubleshooting

Section: Chapter Questions

Problem 8TC

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Given 192.168.31.0 a. How many bits are in the host field for this network? _ b. If we need to set up 30 subnets, how many bits must be used for subnetting? _ c. How many bits are left over that can be used for host addresses? _ d. How many subnets can we create from this? _ total subnet? usable subnet? e. How many hosts could be assigned on each subnet? _ total possible host? Usable hosts? f. What subnet mask will be used? _g. What is the network address for this entire network? _ h. What is the broadcash address for this entire network? _ Show Solution
Consider the IP address : 157.110.88.0. We need 30 subnets in such a way that each subnet may host up to 64 hosts. i) This address is of which type? ii) How many bits will be required for subnet ID? iii) How many usable subnets will be there? iv) What will be the subnet mask? v) What will be the address of 47th host of 25th subnet?
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You are given with an IP address of 112.200.67.132/19. You are asked to make 6 subnets of size 60, 200, 25, 64, 4 and 12. Now, based on your calculation answer the followings: a) What is the first host IP address of subnet size 12? b) What is the broadcast address of subnet size 64? c) What is the last host IP address of the subnet size 12?
Given the Class B network: 185.85.0.0 a. How many bits are in the host field for this network? ________b. If we want to set up subnets to allow up to 100 hosts on each subnet, how many host bits must be used for host addressing? _____________c. How many bits are left over that can be used for subnetting? _____________d. How many subnets can we create from this? ____total subnets ____ usable subnetse. How many hosts could be assigned on each subnet?________ total hosts ______ usable hosts
Given the IP address 180.15.128.0/20. Now, using the given IP address space create five subnets in such a way so that less number of IP address is wasted for each subnet and the subnets will have the following number of hosts SubnetA - 23 hostsSubnetB - 50 hostsSubnetC - 2 hostsSubnetD - 6 hostsSubnetE - 10 hostsNow find out the following for each subnet: a) Network ID b) Broadcast address c) First usable IP address d) Last usable IP address e) Subnet mask Here, while solving the question make sure you are saving IP addresses. For example, SubnetA needs 23 hosts so in SubnetA you can allocate maximum 30 hosts. Follow the table for all the allowed number of hosts and required number of host bits for each subnet: Name of Subnet Maximum number hosts you can allocate Length of Host bits in the IP address cannot exceed SubnetA 30 5-bits SubnetB 62 6-bits SubnetC 2 2-bits SubnetD 6…
Q1: Suppose that a network has an address 195.185.125.0. This network should be divided into 8 subnets. Extract the following task for each of the following subnet Subnet ID Broadcast ID for each subnet Range of IP addresses for each subnet After that determines in which subnet this IP address 195.185.125.160 located.
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An ISP is granted a block of addresses starting with 150.80.0.0/14 . The ISP wants to distribute these blocks to customers as follows:A- the first group has 50 customers, each needs 1024 IP addresses. B- the second group has 4 customers, each needs 512 IP addressesC- the third group has 64 customers, each needs 16 IP addressesSo, Design all the subnets? And find the amount of available IPs after all allocations.
A Network with id: 192.168.0.0 and subnet mask 255.255.0.0 is given to you to split it in such a way thatfollowing classrooms are given adequate number of IPs based on their needs. Each classroom willoccupy its own subnet. The following information for each subnet must be included:  Subnet ID CIDR Subnet Mask First IP usable in the subnet Last IP usable in the subnet Broadcast IP Address for the subnet Classroom1: 8 PCsClassroom2: 400PC and 4 PrinterClassroom 3: 2 PCsClassroom4: 62 PCs and a ServerClassroom5: 24PCs
Consider the following non-default subnet masks: (a) 255.255.248.0, (b) 255.128.0.0 . To which IP address class do they pertain?Write down the following in CIDR notation: (a) IP: 150.160.170.180, Subnet Mask:255.255.224.0; (b) IP: 75.80.85.90, Subnet Mask: 255.252.0.0 Three stations A, B, C and D are connected to a common Ethernet hub. Their IPaddresses and subnet mask are respectively: 200.100.50.67, 255.255.255.252;200.100.50.7, 255.255.255.248; 200.100.50.138, 255.255.255.240 and 200.100.50.1,255.255.255.254. Determine which among these stations can communicate with eachother. You need to show all detailed workings.
Suppose you have the following network requirements, for Given an IP address and mask of 9.0.0.0/8, design an IP addressing scheme using VLSM? How is the efficiency of this method achieved? Use the topology in Figure to answer the questions. a. Network 1 needs to support 330 host addresses. b. Network 2 needs to support 62 host addresses. c. Network 3 needs to support 2 host addresses. d. Network 4 needs to support 520 host addresses. e. Network 5 needs to support 230 host addresses. f. Network 6 needs to support 62 host addresses. g. Network 7 needs to support 2 host addresses. h. Network 8 needs to support 2 host addresses.