We have the sine curve y = sin (x) and I have plotted a box point at (7/3, V3/2). y 2. 3 -1 If we use the parameterization r (t) = (t, sin (t)) , then we know the velocity is: • (6) - (» }). v (t) = (1, cos (t)) and v V We want the principal unit normal at t = r/3. It is the thicker vector. Hint: This is too much work: T' (t) N (t) = |T' (t)| Instead, use the information given above and the concavity of the sine curve and determine the components of N (7/3).
We have the sine curve y = sin (x) and I have plotted a box point at (7/3, V3/2). y 2. 3 -1 If we use the parameterization r (t) = (t, sin (t)) , then we know the velocity is: • (6) - (» }). v (t) = (1, cos (t)) and v V We want the principal unit normal at t = r/3. It is the thicker vector. Hint: This is too much work: T' (t) N (t) = |T' (t)| Instead, use the information given above and the concavity of the sine curve and determine the components of N (7/3).
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 20T
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