We must integrate y = (8x-x2)-(2x) = 6x-x². The limits on the integral correspond to the smallest and largest possible x-values where the two graphs intersect, and so will be (6x-x²) dx.

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We must integrate y = (8x - x2) - (2x) = 6x-x².
The limits on the integral correspond to the smallest and largest possible x-values where the two graphs intersect, and so will be
(6x - x²) dx.
Transcribed Image Text:We must integrate y = (8x - x2) - (2x) = 6x-x². The limits on the integral correspond to the smallest and largest possible x-values where the two graphs intersect, and so will be (6x - x²) dx.
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