We need to use synchronous TDM and combine 20 digital sources, each of 100 Kbps. Each output slot carries 1 bit from each digital source, but one extra bit is added to each frame for synchronization. Answer the following questions:
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- We need to use synchronous TDM and combine 20 digital sources, each of 100 Kbps. Each output slot carries 1 bit from each digital source, but one extra bit is added to each frame for synchronization. Answer the following questions: a. What is the size of an output frame in bits? b. What is the output frame rate?c. What is the duration of an output frame? d. What is the output data rate? e. What is the efficiency of the system (ratio of useful bits to the total bits)?We have 14 sources, each creating 500 characters per second. Since only some of these sources are active at any moment, we use statistical TDM to combine these sources using character interleaving. Each frame carries 6 slots at a time, but we need to add four-bit addresses to each slot. Answer the following questions:(1)What is the size of an output frame in bits?(2)What is the output frame rate?(3)What is the duration of an output frame?(4)What is the output data rate?Two channels one with a bit rate of 190Kbps and another with a bit rate of 180 Kbps are to be multiplexed with Pulse-Stuffing TDM with no synchronization bits. Answer the following questions. i) Calculate size of Frames in bits. ii) Calculate the Frame rate. iii) Calculate the duration of Frame.
- Suppose, BanglaLink has 4 voice channels, each of 60Mbps. They use synchronous TDM to multiplex these channels. If 3 characters at a time are multiplexed (3 characters in each output slot), 1. Draw the first two output frames with arbitrary inputs. 2. What is the size of an output frame in bits? 3. What is the output frame rate? 4. What is the duration of an output frame?Two channels, one at 190Kbps and the other at 180Kbps, are to be multiplexed using Pulse-Stuffing TDM with no synchronisation bits. Please respond to the following questions. I Determine the size of frames in bits. ii) Determine the frame rate. iii) Determine the duration of Frame.4. Three input channels need to be multiplexed using TDM, Their bit rates are 120 kbps, 80 kbps, and 40 kbps, respectively, (a) What is the required output bit rate for the TDM? (b) How to set the relative size of each time slot in one frame? (e) What is the minimum frame size and the corresponding frame rate?
- Ten signals, each requiring 3000 hz, are multiplexed onto a single channel using FDM. How much minimum bandwidth is required for the multiplexed channel? Assume that the guard bands are 300 Hz wide.Q. 2. (b) We need to use Time Division Multiplexing and combine 5 digital sources, each of 800 Kbps. Each output slot carries 4 bits from each digital source, but no extra bit is added to each frame for synchronization. Now, answer the following questions: i) What is the output frame duration? ii) What is the output frame rate? iii) What is the output bit rate? iv) What is the output bit duration? v) What is the size of an output frame in bits? vi) What is the input bit duration?A line has a signal-to-noise ratio of 1000 and a bandwidth of 4000 kHz. What is the maximum data rate supported by this line? If the bandwidth of the channel is 5 kbps, how long does it take to send a frame of 100,000 bits out of this device? What is the maximum data rate of a channel with a bandwidth of 200 kHz if we use four levels of digital signaling?
- Four channels, two with a bit rate of 120kbps and two with a bit rate of 880kbps, are to be multiplexed using multiple-slot TDM with no synchronization bits.Answer the following questions: a. What is the size of a frame in bits? b. What is the frame rate? c. What is the duration of a frame? d. What is the data rate?Question 29: Consider a system with four low-bit-rate sources of 20 kbit/sec, 30 kbit/sec, 40 kbit/sec, and 60 kbit/sec. Determine the slot assignments when the data streams are combined using TDM. Last time some given me this irrelevant answer. If you do not know , do not attempt. Otherwise i will email Bartleby.(2) In asynchronous transmission, why do we keep the number of data bits between the start bit and stop element in a range of 5 to 8 in general? (3) Which steps in PCM lose information in general so that the analog data cannot be fully recovered?