We used an experimental setup like the one shown below. The length of the string between the string vibrator and the pulley is L = 2.00 m. The mass per unit length or linear density of the string is μ = 0.0005 kg/m. The string vibrator can oscillate at any frequency. The hanging mass is 511 g. Frictionless pulley String vibrator μl = dm dx The wavelength of the fifth mode (n = 5) is m. = constant The frequency of the fifth mode (n = 5) is Hz. The tension in the string is close to When the mode of vibration is increased to n = 10, the wave speed of the string will The wave speed on the string is_ m/s. N. Drag answer here Drag answer here Drag answer here Drag answer here Drag answer here Hanging mass 500 125 remain the same 0.8 100 2.0 increase

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We used an experimental setup like the one shown below. The length of the string between the string vibrator and the pulley is L = 2.00 m. The mass per
unit length or linear density of the string is
μ = 0.0005 kg/m. The string vibrator can oscillate at any frequency. The hanging mass is 511 g.
Frictionless
pulley
String
vibrator
μl=
dm
dx
The wavelength of the fifth mode (n = 5) is
m.
The frequency of the fifth mode (n = 5) is
Hz.
The tension in the string is close to
When the mode of vibration is increased to n
= 10, the wave speed of the string will →
2
The wave speed on the string is m/s.
N.
constant
Drag answer here
Drag answer here
Drag answer here
Drag answer here
Drag answer here
m
Hanging
mass
500
125
remain the same
0.8
100
2.0
increase
Transcribed Image Text:We used an experimental setup like the one shown below. The length of the string between the string vibrator and the pulley is L = 2.00 m. The mass per unit length or linear density of the string is μ = 0.0005 kg/m. The string vibrator can oscillate at any frequency. The hanging mass is 511 g. Frictionless pulley String vibrator μl= dm dx The wavelength of the fifth mode (n = 5) is m. The frequency of the fifth mode (n = 5) is Hz. The tension in the string is close to When the mode of vibration is increased to n = 10, the wave speed of the string will → 2 The wave speed on the string is m/s. N. constant Drag answer here Drag answer here Drag answer here Drag answer here Drag answer here m Hanging mass 500 125 remain the same 0.8 100 2.0 increase
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