We will evaluate the following improper integral: ∞ I 1.₁0. dx (x2+3)2 First we will do the indefinite integral S da (x2+3)2 (a) Use the substitution u=²+3 to formulate as an integral with respect to u, filling in the integrand below (remember to use proper Mobius syntax in your function) S 0 (b) Now integrate to get a function of u: du (c) Substitute the value of u interms of x to get an antiderivative in terms of x, we will call this F(x): F(x) =

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