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We will rewrite that as du = 6r? dr. Our goal is now to rewrite the entire integral in terms of our new variable u and its derivative du. Since du = 6x2 dx and our integrand includes r? dr, we will write - du = x² dx. So we can rewrite the integral as follows: |7(2° + 3)° dr = du. This new integral is one that we can do easily. Complete this integral, getting an answer in terms of u.

We will rewrite that as du = 6r? dr. Our goal is now to rewrite the entire integral in terms of our new variable u and its derivative du. Since du = 6x2 dx and our integrand includes r? dr, we will write - du = x² dx. So we can rewrite the integral as follows: |7(2° + 3)° dr = du. This new integral is one that we can do easily. Complete this integral, getting an answer in terms of u.

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...
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5. We will rewrite that as du = 6x² dx. Our goal is now to rewrite the entire integral in terms of our new variable u and its derivative du. Since du = 6x2 dx and our integrand includes r? dr, we will write du = x² dx. So we can rewrite the integral as follows: 1 (2x³ + : u³ du. This new integral is one that we can do easily. Complete this integral, getting an answer in terms of u.
Transcribed Image Text:5. We will rewrite that as du = 6x² dx. Our goal is now to rewrite the entire integral in terms of our new variable u and its derivative du. Since du = 6x2 dx and our integrand includes r? dr, we will write du = x² dx. So we can rewrite the integral as follows: 1 (2x³ + : u³ du. This new integral is one that we can do easily. Complete this integral, getting an answer in terms of u.
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