What are 6-7 subnet masks of the ip address: 195.85.8.0
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What are 6-7 subnet masks of the ip address: 195.85.8.0
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- In which of the following applications, UDP is a suitable transport layerprotocol? (a)In SMTP, a user can send a long e-mail message, which may includemultimedia. When a user sends a message, the recipient does not expectto receive a response quickly. (b)A user needs to download a very large text file from the internet. Theuser doesn’t want part of the file to be missing or corrupted when he/sheopens the file. The delay created between the delivery of the parts arenot an overriding concern for him. (c)In DNS, a client needs to send a short request to a server and to receive a quick response from it. The request and response can each fit in one userdatagram.1. Persistent HTTP requires?a. 2(round trip times) + file transmission timeb. as little as two RTT for all the referenced objectsc. one file transmission timed. as little as one RTT for all the referenced objects 2. UDP has no connection between client & server?a. RCVR extracts sender IP address and portb. sender explicitly attaches IP destination address and portc. three other answers are incorrectd. no handshaking before sending data 3. A socket in computer networks is correctly defined as?a. A combination of IP address and port number, connected by a "/" symbolb. sender explicitly attaches IP destination address and portc. RCVR extracts from the socket, sender IP address and portd. A combination of IP address and port number, connected by a"." symbol 4. The data link layer provides?a. the functional and procedural means to transfer data between network entities and the means to detect and possibly correct errors that may occur in the link layer.b. the functional and procedural…Using https://wiki.dd-wrt.com/wiki/index.php/Linking_Subnets_with_Static_Routes as a base, modify the scenario for VLSM based subnets given the following information. Site address (CIDR Notation) = 192.168.10.0/24 Subnet Included hosts Number of hosts required Subnet ID(CIDR notation) 1 Computer Labs 1 and 2 110 ? 2 Computer Lab 3 60 ?
- Which of the following is NOT an argument against using static routing? O. There is no need for more resources, such as additional CPU or bandwidth. O.b. The routing tables are rather compact, and the amount of maintenance required is low. O.c. If the topology is altered in any way, the configuration will be impacted. The path to the goal does not ever diverge from its usual course.There are events from different web server logs (see below). What can you tell about each row? What is happening in each row? What might be interesting in case of incident investigation? timestamp="09/Mar/2016:11:14:34 +0300" client_ip="73.9.84.166" user_agent="Debian APT-HTTP/1.3 (0.8.16~exp12ubuntu10.26)" url="/precise-security/stable/amd64/Packages.bz2"[09/Mar/2016:11:14:35 +0300] wiki-api.company-realm.ru 25.255.240.122 "GET /_api/frontend/.is_readonly?=&__uid=1120000000006167 HTTP/1.1" 200 "-" "-" "ivanovaa" "companyuid=5986251411438764783" - 717 0.022 0.022[09/Mar/2016:11:14:35 +0300] fml.company-realm.ru 202a:6b8:b010:2048:0:d0c0:5:12 "GET /rest/v2/call/collectPoolFromQueriesRatings/32b86116-e409-11e5-bdc7-0025909427cc?ticket=3201127 HTTP/1.1" 414 "-" "Apache CXF 3.0.4" "-"[09/Mar/2016:11:14:35 +0300] 127.0.0.1:443 127.0.0.1 "GET /ping HTTP/1.0" 200 "-" "KeepAliveClient" "-" "companyuid=-" - 273 0.146 0.146[09/Mar/2016:11:14:34 +0300] st.company-realm.ru 127.0.0.1 "GET…Which of the following is NOT a reason to be against using static routing? O. More resources, such increased CPU power or bandwidth, are not necessary. O.b. Since the routing tables are very small, minimal maintenance is required. O.c. Any modification to the topology will have an impact on the configuration. The path never veers from the objective on the way there.
- An attacker tries to do banner grabbing on a remote web server and executes the following command:$ nmap -sV hackme.com -p 80 He gets the following output:Starting Nmap 7.90 ( http://nmap.org ) at 2020-09-26 22:47 ESTNmap scan report for hackme.com (108.58.137.114)Host is up (0.048s latency).PORT STATE SERVICE VERSION80/tcp open http Apache httpdService detection performed. Please report any incorrect results at http://nmap.org/submit/.Nmap done: 1 IP address (1 host up) scanned in 7.36 seconds What did the hacker accomplish? nmap can’t retrieve the version number of any running remote service. The hacker successfully completed the banner grabbing. The hacker should have used nmap -O host.domain.com. The hacker failed to do banner grabbing as he didn’t get the version of the Apache web server.You have launched an Amazon Elastic Compute Cloud (EC2) instance into a publicsubnet with a primary private IP address assigned, an internet gateway is attached tothe VPC, and the public route table is configured to send all Internet-based traffic tothe Internet gateway. The instance security group is set to allow all outbound trafficbut cannot access the internet. Why is the Internet unreachable from this instance?Let’s consider you have a Class C IP address 204.15.5.0/24. You have to determine whether it is possible to createfollowing network with the given IP address? If yes, what could be the possible ranges of IP addresses for thesubnetworks?
- Say that the Top Level Domain .gov were to suddenly lose all its name servers due to a system crash. Now say that a user on a host example.school.edu wants to FTP to a machine called host51.defense.gov, with which they have never communicated. a. Explain the process that would occur starting with the user’s host until something goes wrong, and explain what would go wrong. b. Now, say that the user had already FTPed some files from host51.defense.gov 10 minutes before the nameservers at .gov crashed. Would connecting again likely work? If so, how would the process that occurred be different?Let’s consider you have a Class C IP address 204.15.5.0/24. You have to determine whether it is possible to createfollowing network with the given IP address? If yes, what could be the possible ranges of IP addresses for thesubnetworks? Let’s consider the above network. If you are using VLSM /CIDR, determine what subnet mask numbers allow therequired number of hosts.For the given IP address 193.105.1.60/27, find the network address, First Address, Last address for the host, Broadcast address and next subnet address. please tery to anser in differnt way coz i dont same this answers to avoid plag try to do it in diffrent way with same answers Step 1 Given IP address 193.105.1.60/27 is a Class C address with CIDR /27 /27 means that the subnet mask is 255.255.255.224 Default subnet mask of Class C is /24 or 255.255.255.0 Here the CIDR is /27, so 3 bit subnetting is used, ie, 3- bit is borrowed from host part to network part. Number of hosts/subnetnetwork = 2m - 2, where m is the remaining bits in the host part, here m=5 =25 - 2=30 hosts Given IP 193.105.1.60/27 is in the network range 193.105.1.32 - 193.105.1.63 Step 2 Network address: It is the first address in the network range. So, 193.105.1.32 is the network address First Host address: It is the first valid host IP address which is…
