What does it mean by line1 of the following C++ statements. void y (int k) //line1 { if ((k%2)==0) cout<< k << " is an even number"; else cout<< k << " is an odd number"; } A.Function name y receives an int-type parameter. The function y does not return anything to the caller. B.Function name y receives an int-type parameter. The function y does return an int-type value to the caller
What does it mean by line1 of the following C++ statements. void y (int k) //line1 { if ((k%2)==0) cout<< k << " is an even number"; else cout<< k << " is an odd number"; } A.Function name y receives an int-type parameter. The function y does not return anything to the caller. B.Function name y receives an int-type parameter. The function y does return an int-type value to the caller
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter6: User-defined Functions
Section: Chapter Questions
Problem 17PE
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What does it mean by line1 of the following C++ statements.
void y (int k) //line1
{
if ((k%2)==0)
cout<< k << " is an even number";
else
cout<< k << " is an odd number";
}
A.Function name y receives an int-type parameter. The function y does not return anything to the caller.
B.Function name y receives an int-type parameter. The function y does return an int-type value to the caller.
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