What function do you know from calculus is such that its first derivative is itself? (Do not use the function f(x) = 0.) f(x) = The above function is a solution of which of the following differential equations? Oy' = y² Oy' = y Oy' = ev Oy' = 2y Oy' = 1 What function do you know from calculus is such that its first derivative is a constant multiple k of itself? (Do not use the function f(x) = 0.) f(x) = The above function is a solution of which of the following differential equations? Oy' = yk Oy' = k O y'= y + k Oy' = eky Oy' = ky

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