What happens to potential energy As the satellite comes closer to the earth
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A: v = 1200/60 = 20rpsω = 2πv = 2×π×20 = 40π rad/secMagnitude of acceleration = rω2 = 0.30×(40π)2 = 473...
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A: I've solved a similar question earlier, you may change the values and everything is same.
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A: False
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A: 1250 m/s
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A: Option a is
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A: Formula used:Resistance , R =ςLA here ς= 1.68 ×10-8 , L =4.9×10-3 , A =π×1.7 ×10-322
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A: given,ax(t)=-8+32tinitial velocity Ux=15m/sax(t)=dvx(t)dt∫0tax(t)dt=∫uxvxvx(t)∫uxvxvx(t)=∫0t(-8+32t)...
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A: The electron makes a transition from n = 5 to n = 2. ΔE=R(1n21–1n22)= 45.774 X 10-20 J Frequency, v ...
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A: I belive only one figure and option is provided. It's incomplete . Please give complete picture.
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A: To answer: Is it more convenient to use wavefunctions with definite energy?
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A: The resultant R be defined as the resultant vector. Then R be given as, R2=A2+B2+2ABcosθ
What happens to potential energy As the satellite comes closer to the earth
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