What is missing from the join statement? SELECT EmployeeName, Salary FROM Employee, Department WHERE Salary > 50000;
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- The team wants to track potential list of users who may have forgotten their items on the cars. Therefore, you need to return USER_FIRST_NAME, USER_LAST_NAME, TRAVEL_START_TIME, TRAVEL_END_TIME information from the USERS and TRAVELS tables connected inside a JOIN statement by the USING function and USER_ID field5. For each order, list the order number, quoted price and the item description, when the category is TOY.6. Use the inner join syntax to show the customer name and the matching order dates.Rewrite the following query using a join statement (no subqueries). (0.5) SELECT productid, productname, productprice FROM product WHERE productid IN (SELECT productid FROM soldvia GROUP BY productid HAVING SUM(noofitems) > 3);
- show all the department names, along with their managers full names, job titles and salaries. note: departments without a manager will not be shown. it must be done using join syntax.I need help with a SELECT statement that returns the cust_id and the total number of orders for each customer; using a outer join with table aliases.Write a Query using JOINS to display the Customer Name, Email, Delivery Address and Final Price of all orders whose Final Price is atleast 200 dollars.
- Because the SELECT clause contains the Customer* column, which clause must be included for the query to execute successfully? 1 SELECT customer#, COUNT(*)2 FROM customers JOIN orders USING(customer#)3 WHERE orderdate > '02-APR-09'4 GROUP BY customer#5 HAVING COUNT(*) > 2;Create a query that SELECT all of the EMPLOYEES from the EMPLOYEE TABLE that are Mangers. Include Employee ID first name, Lastname and Salary (Hint: Self Join)Without re-creating the table write one sql statement to answer this question. Change the definition of Riverview_customer to include the customer type, but name this column custtype. Put a restriction on the table to ensure that the customer types will include values of O, L and N. Name this restriction valid_custtypes
- Show the students’ ID and the courses number the students took (don’t include currently taking) and other courses that are not taken by any students by using one query statement. Hint: use LEFT JOINUse the following table to answer the questions below: Table name: Customers Column Name Role Data Type Length Constraint customerID stores the ID of a customer Char 5 Primary key custFName stores the first name of a customer Varchar2 35 Cannot be null custLName Stores the last name of a customer Varchar2 35 Cannot be null custGender Store the gender of a customer Char 1 It should be ‘M’ or ‘F’ custDOB Stores the date of birth of a customer Date custIncome Store the income of a customer Number 4 Write in SQL a command that creates the table Customers according to the above description (2 marks). Write in SQL a statement that adds a new column named accountID of type Char(8). This column should be defined as a foreign key that relates the table Customers to the table Account (1.5 marks). Write in SQL a command that deletes the customers whose date of birth is after 22-Dec-1990 (1.5 Marks).…Create a query to show the Technician Number, Last Name, First Name, Client Number,and Client Name for clients whose technician number is 23 (use Boolean variables).Save your query
