What is the average power of the signal a(t) = 6cos 2000nt + 2sin(8000nt) + 4cos(4000at) ?

Q: the minimum sampling rate (according to Nyquist frequency) for the signal [ x(t) =2 ? cos 6000 Ttt +…

A: Hello Student. Greetings Hope you are doing great. I will try my best to answer your question. Thank…

Q: the minimum sampling rate (according to Nyquist frequency) for the signal [ x(t) =2 * ? cos 600O ttt…

A: The given signal is, x(t) = 2cos6000πt + 5cos10000πt Minimum sampling rate is: S = 2 *…

Q: the minimum sampling rate (according to Nyquist frequency) for the signal [ x(t) =2 * ? cos 6000 Ttt…

A: Given x(t)=2*cos6000*pi*t+5*cos10000*pi*t fm=maximum(6000,10000)/2 fm=10000/2=5000Hz

Q: Compute the energy of the signal x(t) = 2cos(nt) in one period time and also compute the average…

A: t=(0:1); % one time period x_t=2*cos(pi*t); % given signal   Energy = norm(x_t,2)^2 % the energy of…

Q: The average signal rate of 2BlQ is a. N b. N/2 c. N/4 d. N/6

A: Question The average signal rate of 2BlQ is a. N b. N/2 c. N/4 d. N/6

Q: 2. For the given signal, x(t)= 5 + sin(6t) + 2cos(8t), perform the following basic operations on it:…

A: Hello student Greetings from my side Hope you are doing great. I will try my best to answer your…

Q: 2. For the given signal, x(t)= 5 + sin(6t) + 2cos(8t), perform the following basic operations on it:…

A: Requirements :- on matlab please Approach :- Steps :- Find the best range so that th graph…

Q: b- What is the SNR for the following signal? time 0 1 3 60 8 10 signal 0.1 0.12 1.1 1.12 1.3 0.91…

A:

Q: When pulse duration 0.001ms and fm 3KHZ ,the spectrum of the sampled signal is Your answer

A: 3

Q: B) Draw and find the BASK signal if maximum carrier amplitude is 14V and f.=0.1MHz and the input…

A:

Q: To quantize a signal with 24 data levels, we need .......

A: Please give positive ratings for my efforts. Thanks.   ANSWER   Here, number of levels            =…

Q: Draw the waveform for the three-by sequence Ox93, Ox11, Ox41 being transmitted by UART at 9600 baud,

A: SPBRG if BRGH=0 is 15.27(dec) , F.45(Hex)SPBRG if BRGH=1 is 64.10(dec) , 40.19(Hex)

Q: How many bits are required to sample an incoming signal 4000 times per second using 256 different…

A: To calculate the number of bits, we have the following formula-  The number of bits =Signal times…

Q: Plot the following discrete-time signals over the range -10 s ns 10: i oln-3] i. uln-31 ii. r(n-3)…

A: OUTPUT:

Q: Given the input signal x[n] = [1, 1, 1, 4] and h[n] = [-1, 0, 1]. Determine y[1] O 1 O-1 O 2

A: option B is correct answer ie, y[1]=-1

Q: Given the input signal x[n] = [1, 2, 0, 2] and h[n] = [-1, 2]. Determine the y[1] O 2 O 3 O -1

A: The correct option for the given question is as follows.

Q: The Nyquist rate for a continuous-time signal (x) is X(t)= 6 cos 50rtt + 20 sin 300 t t - 10 cos 100…

A: The frequencies present in the given signal are F1=25Hz, F2=150Hz, F3=50HzThus Fmax=150Hz and from…

Q: A continuous-time signal is sampled with a sampling time interval of 0.0012 sec. then the frequency…

A: Please give positive ratings for my efforts. Thanks.   ANSWER

Q: A company produced a mobile phone equipment. Analyze the Shannon limit for information capacity of…

A: - We need to talk about shannon limit for information capacity. We have (s/n) ratio to be :: 10dB.

Q: A PWM signal has a period of 100 millseconds. The initial pulse width is 10 millseconds. This means…

A: Resolution =( pulse width / period ) * 100 Resolution = (10 /100) *100                   = ( 1 /10)…

Q: A signal travels from point A to B. At point A the signal power is 100W. At point B the power is 80.…

A: I Have answered this question in step 2.

Q: A continuous-time signal is sampled with a sampling time interval of 0.004 sec. then the frequency…

A: The time interval TS seconds between two successive samples is called the sampling interval, and its…

Q: A continuous-time signal is sampled with a sampling time interval of 0.004 sec. then the frequency…

A:

Q: The transmission impairment that refers to a signal with high energy in a very short time is…

A: In this answer I will be discussing about the Impulse Noise.

Q: If a signal has a frequency of 30KHZ what is the period in Microseconds?

A: given the frequency=30KHZ   The formula is,        f=1/s given     30=1/s   hence s=1/30= 0.33

Q: NRZ-L and NRZ-I both have an average signal rate of a. N b. N/8 c. N/4 d. N/2

A: Answer :-  ( d ).   N/2   NRZ-L and NRZ-I both have an average signal rate of N/2 Bd.

Q: A non-periodic composite signal contains frequencies from 10 to 30kHz. The peak amplitude is 10V for…

A: Given: Non-periodic composite signal frequency range =10 to 30 kHz Peak amplitude =10 V and 30 V To…

Q: A signal travels from point A to point B. At point A, the signal power is 100 W. At point B, the…

A: The attenuation in decibels is -0.46   Formula: dB = 10 log10 (90 / 100) = -0.46 dB

Q: The PAM modulated signal has     constant amplitude of the carrier signal.     varied amplitude…

A: Below is the answer:

Q: The most common ADC seen in telecommunications based on audio signals is(a) flash ADC(b) successive…

A: Given: The most common ADC seen in telecommunications based on audio signals is(a) flash ADC(b)…

Q: Signal rate for Manchester coding is that for NRZ scheme. a. 4 times O b. 2 times O c. 3 times d.…

A: Signal rate: A number of signal elements sent in a second and is measured in bauds is called the…

Q: Q: Assume you have the modulated signal of (t) = A sin(4000nt + 90) + Bsin(3600nt + 90) +…

A:

Q: Q: Assume you have the modulated signal of ø(t) = A sin(4000nt + 90) + Bsin(3600nt + 90) +…

A:

Q: For Sin wave signal, which one is not correct? O a. It is aperiodic signal. O b. It is continuous…

A: For The Sin wave signal, which one is not correct? a) it is a periodic signal. b)it is a continuous…

Q: A PWM signal has a period of 100 millseconds. The initial pulse width is 10 millseconds. This means…

A: Pulse width modulation is a powerful technique used to control analog circuits using digital…

Q: The Nyquist sampling rate required to sample the signal x(t)= [cos(6000 nt).cos(2000 nt) is equal…

A: Given signal cos(6000πt)cos(2000πt) From the formula cos(a+b)+cos(a-b)=2(cosa.cosb)…

Q: Using the Nyquist theorem, calculate the minimum sampling rate for an analog signal with frequencies…

A: Here, I have to provide a solution to the above question.

Q: Given the following timing waveform for Y, draw D and E. 10ns Sns 10ns 2ns 10 20 30 wire #3 D; //…

A:

Q: For SNR of 12.33 dB and signal power .4 of 22.23 mW, the value of noise power :is 1.3 mW O 0.3 W O…

A: Formula=SNR=Signal power/ Noise power Given SNR in dB so we will first convert it into normal.…

Q: A signal is measured at two different points. The power is P1 at the first point and P2 at the…

A: The decibel is the logarithm of the ratios of the powers hence, the formula is represented as…

Q: A signal is measured at two different points. The power is P1 at the first point and P2 at the…

A: Asked: A signal is measured at two different points. The power is P1 at the first point and P2 at…

Q: Plot the following signals. Label x-axis with time(s) for continuous time signals, and 'n' for…

A: Required: on matlab

Q: When the mobile is moving in the direction of signal source with speed = 120 km/hour and the carrier…

A: The bandwidth of the signla u1c1 is 20khz

Q: t < 0} f(t) te Calculate the laplas transform of the signals given below.

A: The laplas transform of the signals

Q: In same as the amplitude of the carrier frequency. the peak amplitude of one signal level is 0; the…

A: The Answer :

Q: 4. To convert an analog signal, with bandwidth of 16 MIHZ, to a digital signat, the sampling…

A: Answer :-

Q: which is trefers to time shifting of discrete time signal: a. x(n) = z(n-k) b. x(n) = z(-n-k) c.…

A: x[n] = z[n-k] referes to time shifting of discrete time signal

Q: Nyquist theorem specifies the minimum sampling rate to be twice the highest frequency of a signal…

A: here have to determine Nyquist theorem specifies the minimum sampling rate to be twice the highest…

Q: If the baud rate is 400 for a QPSK signal, the bit rate is ________ bps. a. 100 b. 400 c. 800 d.…

A: Given, Baud rate of QPSK signal = 400 We have to calculate the bit rate.

Q: If the baud rate is 400 for a QPSK signal, the bit rate is ________ bps. a. 100 b. 400 c. 800 d.…

A: Bit Rate: Bit rate may be described because the quantity of bit durations consistent with 2nd. And…