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What is the best implementation of the Binary Search in Java. Which data structure would you use to get the best results (time and space complexity)? Explain in detail.

What is the best implementation of the Binary Search in Java. Which data structure would you use to get the best results (time and space complexity)? Explain in detail.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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What is the best implementation of the Binary Search in Java. Which data structure would you use to get the best results (time and space complexity)? Explain in detail. 

Binary Search V1 Algorithm: BinarySearch v1(arr[], min, max, key) if max < min then return false < Mid Mid Mid < else mid = (max + min) / 2 if list[mid]> key then return BinarySearch_v1(arr[], min, mid – 1, key) else if list[mid]< key then return BinarySearch_v1(arr[], mid + 1, max, key) else return mid Binary Search V2 Algorithm: BinarySearch_v2(arr[], min, max, key) if min < 1 then return -1 else mid1 = min + (max - min) / 3 mid2 = max + (max - min) / 3 if arr[mid1]=key then return mid1 < Mid1 Mid1 Mid1 < x < Mid2 Mid2 Mid2 < if arr[mid2] = key then return mid2 if list[mid1]> key then return BinarySearch_v2(arr[], min, mid1 – 1, key) else if list[mid2]< key then return BinarySearch_v2(arr[], mid2 + 1, max, key) else return BinarySearch_v2(arr[], mid1 + 1, mid2 – 1, key)
Transcribed Image Text:Binary Search V1 Algorithm: BinarySearch v1(arr[], min, max, key) if max < min then return false < Mid Mid Mid < else mid = (max + min) / 2 if list[mid]> key then return BinarySearch_v1(arr[], min, mid – 1, key) else if list[mid]< key then return BinarySearch_v1(arr[], mid + 1, max, key) else return mid Binary Search V2 Algorithm: BinarySearch_v2(arr[], min, max, key) if min < 1 then return -1 else mid1 = min + (max - min) / 3 mid2 = max + (max - min) / 3 if arr[mid1]=key then return mid1 < Mid1 Mid1 Mid1 < x < Mid2 Mid2 Mid2 < if arr[mid2] = key then return mid2 if list[mid1]> key then return BinarySearch_v2(arr[], min, mid1 – 1, key) else if list[mid2]< key then return BinarySearch_v2(arr[], mid2 + 1, max, key) else return BinarySearch_v2(arr[], mid1 + 1, mid2 – 1, key)
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