What is the big O notation for this function?
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What is the big O notation for this function?
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- def get_numbers(): user_input = input() values = [] for token in user_input.split(): values.append(int(token)) return values def print_selected_numbers(): numbers = get_numbers() for number in numbers: if (number % 2) != 0: print(number) print_selected_numbers() Input 1 7 4 19 2 10 what is the output please explainIn Java Write a Java Program to find the factorial of a number. The factorial of nonnegative integer n (denoted by n!) is the product of all positive integers less than orequal to n. Example: 4! = 4 × 3 × 2 × 1 = 24. The value of 1! Is 1 and the value of0! Is 1 too. Do not accept negative numbers.Sample Run:Enter a positive integer: -1Invalid entry.Enter a positive integer: -15Invalid entry.Enter a positive integer: 5Factorial of 5 = 120The Problem The Mastermind game board game is a code breaking game with two players. One player (your program) becomes the codemaker, the other the codebreaker. The codemaker (your program) creates a 4 digit secret code which is randomly generated by the supplied code below and the codebreaker tries to guess the 4 digit pattern. import randomsecretCode =[]for i in range (0,4): n = random.randint(1,9) secretCode.append(str(n)) print (secretCode) # take this out when you are playing the game for real because it is a secret The secret code pattern generated above will consist of any of the digits 1-9 and can contain multiples of the same digit. Your program should then tells the codebreaker which digits should be in their guess by displaying a sorted list of the digit characters contained in the secret code python list . Use the loopfor digit in sorted(secretCode): #display each digit on the same line for the player to see; there could be duplicate digits in the secret Prompt…
- Write an application that reads an integer value from the user and prints the sum ofall even integers between 2 and the input value, inclusive. Print an error message ifthe input value is less than 2. Use Java. Sample Run Examples: Example 1:the user enters 14Output: Sum: 56Example 2:the user enters 1Output: Error number must be greater than 11. Write an algorithm that asks the user to enter ten numbers and then prints the largest one.2. Write an algorithm that asks the user to enter a positive integer n and prints the sum of the divisors of n.01. Please _Given an integer num, repeatedly add all its digits until the result has only one digit, and return it. Example 1: Input: num = 38 Output: 2 Explanation: The process is 38 --> 3 + 8 --> 11 11 --> 1 + 1 --> 2 Since 2 has only one digit, return it. Example 2: Input: num = 0 Output: 0 Constraints: 0 <= num <= 231 - 1 Follow up: Could you do it without any loop/recursion in O(1) runtime? //code here class Solution {public: int addDigits(int num) { }}; //.
- ntegers outerRange and innerRange are read from input. Complete the outer while loop so the inner loop executes (outerRange + 1) * innerRange times. Ex: If the input is 6 5, then the output is: Inner loop ran 35 times import java.util.Scanner; public class LoopCounter { public static void main (String[] args) { Scanner scnr = new Scanner(System.in); int outerRange; int innerRange; int count; int i; int j; outerRange = scnr.nextInt(); innerRange = scnr.nextInt(); count = 0; i = 0; while (/* Your code goes here */) { j = 0; while (j < innerRange) { ++count; ++j; } ++i; } System.out.println("Inner loop ran " + count + " times"); } }(java programming language) Given f(x) = x+ x2/2+ x3/3+…… xn/n. Using do-while, write a program to compute f(x) for given x andn. The user should enter x and a positive integer n. Save your file as Q3.JavaZombie World ------------ input 10 2 4 9 output YES */ #include<iostream> using namespace std; int bubbleSort(int a[],int n) { int temp; for(int i=0;i<n-1;i++) { for(int j=0;j<n-i-1;j++) { if(a[j]<a[j+1]) { temp = a[j]; a[j]=a[j+1]; a[j+1]=temp; } } } } int main(int argc, char const *argv[]) { int b,n; cin>>b>>n; int z[n]; for(int i=0;i<n;i++) { cin>>z[i]; } bubbleSort(z,n); int flag = 1; for(int i=0;i<n;i++) { if(b<z[i]) { flag =0; break; } b = b - (z[i]%2 + z[i]/2); } if(flag==1) cout<<"YES"; else cout<<"NO"; return0;.
- Write a program that reads integers, finds the largest of them, and counts its occurrences. Assume the input ends with number 0. Suppose you entered 3 5 2 5 5 5 0; the program finds that the largest is 5 and the occurrence count for 5 is 4. (Hint: Maintain two variables, max and count. max stores the current max number and count stores its occurrences. Initially, assign the first number to max and 1 to count. Compare each subsequent number with max. If the number is greater than max, assign it to max and reset count to 1. If the number is equal to max, increment count by 1.)In Python, The function add_char_counts takes three parameters: a string s and two strings of length 1, char1 and char2, and returns the total number of times either char1 or char2 appears in s. For example, the word "scallions" has 2 s's and 1 n, so add_char_counts("scallions", "s", "n") returns 3. Hint: Use a string method to help solve this problem (count). You do not need an accumulator. For example: Test Result print(add_char_counts('Indiana', 'a', 'b')) 2 print(add_char_counts('BAHAMAS', 'A', 'B')) 4 print(add_char_counts('Mississippi', 'i', 'M')) 5 print(add_char_counts("spam spam spam spam", "s", "p")) 8public class Question1 {public static void main(String[] args) {double val;int counter = 0;int numIterations = 0;/*** Part a: Implement a branching condition that increases counter by 1 if val is larger than 0.5*/val = Math.random();/*** Part b: Add a loop around the code created in Part a that continues until counter equals 3.*//*** Part c: Use the variable numIterations to count how many times your loop in Part b iterates*/System.out.println("Number of Iterations until 3 random values greater than 0.5 were generated: "+ numIterations);}}
