What is the Big(0) of the following algorithm?i = 1%3Dloop (i <= 5)j = 1loop (j <= n)k = 1loop (k <= n)print(i, j, k)k = k + 1end loopj = j * 2end loop%3Di = i + 1end loopO(n squared)O(n)O(n factorial)O(nlog(n))O(n cubed)O Ollog(n)

The solution to the given problem is below.

What is the Big(O) of the following algorithm? i = 1 loop (i <= 5) j = 1 loop (j <= n) k = 1 %3D loop (k <= n) print(i, j, k) k = k + 1 end loop j = j * 2 end loop i - і + 1 = i + end loop O(n squared) O Oln) O O(n factorial) O O(nlog(n)) O(n cubed) O Ollog(n))

What is the Big(O) of the following algorithm? i = 1 loop (i <= 5) j = 1 loop (j <= n) k = 1 %3D loop (k <= n) print(i, j, k) k = k + 1 end loop j = j * 2 end loop i - і + 1 = i + end loop O(n squared) O Oln) O O(n factorial) O O(nlog(n)) O(n cubed) O Ollog(n))

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Counting sort

The counting sort algorithm sorts an array’s contents by counting the repetition of each element that occurs in the array. A counting sort algorithm is a stable algorithm that works the best when the range of elements in the array is small, say for example from 0 to 9. The count which is the number of repetitions of an element in the array is mapped to an index of an auxiliary array, which is then saved in an auxiliary array. The counting sort algorithm has a stable time complexity of the order of O(size of array + size of auxiliary array). Let’s discuss the algorithm in detail as follows.

Question

What is the Big(0) of the following algorithm?
i = 1
%3D
loop (i <= 5)
j = 1
loop (j <= n)
k = 1
loop (k <= n)
print(i, j, k)
k = k + 1
end loop
j = j * 2
end loop
%3D
i = i + 1
end loop
O(n squared)
O(n)
O(n factorial)
O(nlog(n))
O(n cubed)
O Ollog(n)

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