"What is the end behavior for this equation? ƒ (x) = −3x² − 4x+7 -

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter3: Polynomial And Rational Functions
Section3.1: Quadratic Functions And Models
Problem 54E: Sales A soft-drink vendor at a popular beach analyzes his sales records and find that if he sells x...
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What is the end behavior for this equation?
f(x) = -3x² - 4x + 7
O As a →→→→∞0, f (x)
-
→→→∞, and as a →→∞, f (x) →→→∞
O As x→→→→∞, f (x) →→→∞, and as a →→∞, f (x)
-
O As x→→→→∞, f (x)→→∞, and as x→→→∞, f (x) →→∞
O As a →→∞, f (x) →→∞, and as a →→→∞, f (x) →
→∞
Transcribed Image Text:What is the end behavior for this equation? f(x) = -3x² - 4x + 7 O As a →→→→∞0, f (x) - →→→∞, and as a →→∞, f (x) →→→∞ O As x→→→→∞, f (x) →→→∞, and as a →→∞, f (x) - O As x→→→→∞, f (x)→→∞, and as x→→→∞, f (x) →→∞ O As a →→∞, f (x) →→∞, and as a →→→∞, f (x) → →∞
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I understand that in standard form the value is -3, therefore, the parabola opens up negative and therefore the end behavior is negative. I do not understand how to get the middle two infinity parts. As I highlighted

As xx, f(x) →∞, and as a → ∞, f(x).
Transcribed Image Text:As xx, f(x) →∞, and as a → ∞, f(x).
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