What is the equation of the curve that passes through the point (0, 3) and has a slope at any point defined by y O y(x) = 2cos (x) + 3 – n O y(x) = 2sin-'(x) + 3 O y(x) = 2sin(x) – 3 – n O y(x) = 2cos(x) – 3 + n

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter1: Equations And Graphs
Section1.3: Lines
Problem 3E
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What is the equation of the curve that passes through the point (0, 3) and has a slope at any point defined by y
О Уух) %3D 2сos"(x) + 3 — п
O y(x) = 2sin-1(x) + 3
о ух) %3D2sin "(x) — 3 — п
-
O y(x) = 2cos (x) – 3 + t
Transcribed Image Text:What is the equation of the curve that passes through the point (0, 3) and has a slope at any point defined by y О Уух) %3D 2сos"(x) + 3 — п O y(x) = 2sin-1(x) + 3 о ух) %3D2sin "(x) — 3 — п - O y(x) = 2cos (x) – 3 + t
dy
ах -6 if y(1) %3D-2.
Solve
dx
О у/х) %3D 6х — 2
О у/х) %3D 6х —-8
О У/х) 3D 6х +8
О Уух) %3D 6х + 2
Transcribed Image Text:dy ах -6 if y(1) %3D-2. Solve dx О у/х) %3D 6х — 2 О у/х) %3D 6х —-8 О У/х) 3D 6х +8 О Уух) %3D 6х + 2
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