What is the equation of the curve that passes through the point (0, 3) and has a slope at any point defined by y O y(x) = 2cos (x) + 3 – n O y(x) = 2sin-'(x) + 3 O y(x) = 2sin(x) – 3 – n O y(x) = 2cos(x) – 3 + n
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Solved in 2 steps with 1 images
- Find an equation of the curve that passes through the point (0, 1) and whose slope at (x, y) is -x/(2y).Find an equation of the curve that passes through the point (0, 2) and whose slope at (x, y) is x y .Find an equation of the curve that passes through the point (0, 4) and whose slope at (x, y) is x/y.
- 1. Find the equations of all tangent lines to the curvex2+4y2=8 that pass through the point(−4,0).Find the slope of the curve y=x2−3x−4 at the point P(2,−6) by finding the limiting value of the slope of the secant lines through point P.Find the equation of the line tangent to the curve y =8/x2+4 at the point(2, 1).