What is the equation of the tangent line and normal line to the curve y = -8 at (4, – 4)? Оа. TL: 2x + y -4%3D0 NL: x- 2y – 12 = 0 O b.TL: 2x -y + 4 = 0 NL: x + 2y + 12 = 0 Ос. TL: х + 2у + 12 %3D0 NL: 2x - y+ 4 = 0 O d.TL: x - 2y – 12 = 0 NL: 2x +y - 4 =0

Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter6: Topics In Analytic Geometry
Section6.2: Introduction To Conics: parabolas
Problem 4ECP: Find an equation of the tangent line to the parabola y=3x2 at the point 1,3.
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What is the equation of the tangent line and normal line to the curve y =
-8
at (4, – 4)?
Оа. TL: 2x + y -4%3D0
NL: x- 2y – 12 = 0
O b.TL: 2x -y + 4 = 0
NL: x + 2y + 12 = 0
Ос. TL: х + 2у + 12 %3D0
NL: 2x - y+ 4 = 0
O d.TL: x - 2y – 12 =0
NL: 2x +y - 4 =0
Transcribed Image Text:What is the equation of the tangent line and normal line to the curve y = -8 at (4, – 4)? Оа. TL: 2x + y -4%3D0 NL: x- 2y – 12 = 0 O b.TL: 2x -y + 4 = 0 NL: x + 2y + 12 = 0 Ос. TL: х + 2у + 12 %3D0 NL: 2x - y+ 4 = 0 O d.TL: x - 2y – 12 =0 NL: 2x +y - 4 =0
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