What is the lifetime of each variable? when does it begin? when does it end
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Can you answer this question for me because i don't understand it, can you please be every specfic with answer so i CAN understand it. Can you label each part.
question:
What is the lifetime of each variable? when does it begin? when does it end?
![String* x;
int main () {
}
P();
q();
int p() {
}
= new String [10];
X =
int q () {
}
delete x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbebdfd8f-c6ea-4dde-abb0-eb5c1c681005%2Fcabe2793-d002-4aad-89b3-59333e4a86fb%2Fpx0fu3_processed.jpeg&w=3840&q=75)
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- private static String extractVowelHelper(String str, int start, String vowels) { // base case // recursive step }java Use Map data structure Write a method that returns the frequency of each characters of a given String parameters If the given String is null ,then return nullClass Utilities { Method Details addDelimiter: public static java.lang.String addDelimiter(java.lang.String str, char delimeter) Returns a string where characters are separated by the specified delimeter character. A string with a single character will not have a delimeter added. The space character is consider a character (similar to character 'A'). You can assume str will never be the empty string. You may not use an auxiliary method in order to implement this method. Your implementation must be recursive and you may not use any loop construct. Note: In java given two characters a and b, a + b will not create a string. To create a string, append a to the empty string and the result to b. From the String class, the only methods you can use are length(), isEmpty(), charAt() and substring. Do not use ++ or -- in any recursive call argument. It may lead to an infinite recursion. For example, use index + 1, instead of index++. Parameters: str - delimeter - Returns: String with characters…
- Java Without using any java functions, data structures, libraries, string builder or anything complicated. Please make a program that takes out the tokens in a string. For example "90+5" -> 90 + 5 Make It so it is null if string is empty " " --> null Make it so it is null if expression is invalid "++7 - 0" --> null and "..7 + 0" --> null Use this for loop to iterate through the list for (int i = 0; i < exprn.length(); i++) {Public class Utilities { getDigits Method: public static java.lang.String getDigits(java.lang.String str) Returns a string with the digits (if any) present in the str parameter. You can assume str will never be null. You can use Character.isDigit() to determine whether a character is a digit. You may not use an auxiliary method in order to implement this method. Your implementation must be recursive and you may not use any loop construct. From the String class, the only methods you can use are length(), isEmpty(), charAt() and substring. Do not use ++ or -- in any recursive call argument. It may lead to an infinite recursion. For example, use index + 1, instead of index++. Parameters: str - Returns: String with digits or empty stringString Pair // Problem Description // One person hands over the list of digits to Mr. String, But Mr. String understands only strings. Within strings also he understands only vowels. Mr. String needs your help to find the total number of pairs which add up to a certain digit D. // The rules to calculate digit D are as follow // Take all digits and convert them into their textual representation // Next, sum up the number of vowels i.e. {a, e, i, o, u} from all textual representation // This sum is digit D // Now, once digit D is known find out all unordered pairs of numbers in input whose sum is equal to D. Refer example section for better understanding. // Constraints // 1 <= N <= 100 // 1 <= value of each element in second line of input <= 100 // Number 100, if and when it appears in input should be converted to textual representation as hundred and not as one hundred. Hence number…
- def distinct_last_name(full_names): ''' Question 5 You are given a large string that contains a list of full names separated by commas, you are asked to retrieve all distinct last names and store them in a set. Args: full_names (string) Returns: list >>> distinct_last_name('Harry Sharp, Chen Zhou, Tong Zhou, Dey Santanu') {'Sharp, Zhou, Santanu'} ''' # print(distinct_last_name('Harry Sharp, Chen Zhou, Tong Zhou, Dey Santanu'))python question: Write a code that takes a sentence as an argument and places its words in a list of words in alphabetical order If the sentence is: "Am I good" The function returns: ['Am', 'I', 'good']In C++ commas must be there. main.cpp #include <vector>#include <string>#include <iostream> using namespace std; // TODO: Write method to create and output all permutations of the list of names.void PrintAllPermutations(const vector<string> &permList, const vector<string> &nameList) { } int main() { vector<string> nameList; vector<string> permList; string name; // TODO: Read in a list of names; stop when -1 is read. Then call recursive method. return 0;}
- emacs/lisp function Write a function that takes one parameter that is a list of numbers and returns true (t) if all the elements of the list are multiples of the first one and nil otherwise.C++ program Reverse Phone Book you are given map<string,int> object named phone_book. write a program that produces a map<int,set<string>> object from it named reverse_phone_book.The data is that for each phone number, the reverse phone book contains all the names who have that phone number.City and State. Extract the city name and state from strings like “Utica, NY” and “Los Angeles, CA”. Assume the state is always the last two characters in the string, the city name has at least one character, there is a comma following the city name, and a single space after the comma. Use the split method to separate the city name from the state (Notice the city name will still have a comma at the end). The following attachement is a sample execution:
