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What is the magnetic field at the origin (point P) due to the two current carrying wires illustrated below? Use sin(45) = cos(45°)=- √√2 and =1×10 Tm/A. 2 12 = 8A I₁ = 12A P y X 1m x I I | 1m X 140 4t

What is the magnetic field at the origin (point P) due to the two current carrying wires illustrated below? Use sin(45) = cos(45°)=- √√2 and =1×10 Tm/A. 2 12 = 8A I₁ = 12A P y X 1m x I I | 1m X 140 4t

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What is the magnetic field at the origin (point P) due to the two current carrying wires 52 2 illustrated below? Use sin(45°) = cos(45°) = 12 = 8A 1₁ = 12A 11 (x P y 1m x I 1m X 140 and =1×10¹ Tm/A 4π
Transcribed Image Text:What is the magnetic field at the origin (point P) due to the two current carrying wires 52 2 illustrated below? Use sin(45°) = cos(45°) = 12 = 8A 1₁ = 12A 11 (x P y 1m x I 1m X 140 and =1×10¹ Tm/A 4π
A. (−16î + 8j) ×10-?T B. (-32î + 8j) ×10^°T C. (-24i +16j) × 10-7 T (-24i – 8j) × 10– T + 24j) ×10-?T D. E. (Pi }2 جالات
Transcribed Image Text:A. (−16î + 8j) ×10-?T B. (-32î + 8j) ×10^°T C. (-24i +16j) × 10-7 T (-24i – 8j) × 10– T + 24j) ×10-?T D. E. (Pi }2 جالات
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