what is the problem with the following code. Give reason for your answer. public class MyClass\{ public static void main(String[] args) \{ int n[]={1,3,5,6} ; int b[]; b=n; \} \}
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what is the problem with the following code. Give reason for your answer. public class MyClass\{ public static void main(String[] args) \{ int
n[]={1,3,5,6}
; int b[];
b=n;
\} \}
Step by step
Solved in 4 steps with 2 images
- Please implement in Java implement a keyed bag in which the items to be stored are strings (perhaps people’s names) and the keys are numbers (perhaps Social Security or other identification numbers). So, the in- sertion method has this specification: public void insert(String entry, int key);// Precondition: size( ) < CAPACITY, and the // bag does not yet contain any item// with the given key.// Postcondition: A new copy of entry has// been added to the bag, with the given key. When the programmer wants to remove or retrieve an item from a keyed bag, the key of the item must be specified rather than the item itself. The keyed bag should also have a boolean method that can be used to determine whether the bag has an item with a specified key. In a keyed bag, the pro- grammer using the class specifies a particular key when an item is inserted. Here’s an implementation idea: A keyed bag can have two private arrays, one that holds the string data and one that holds the corresponding…public class Soru32{ // Returns length of LCS for X[0..m-1], Y[0..n-1] static void lcs(String X, String Y, int m, int n) { int[][] L = new int[m+1][n+1]; // Following steps build L[m+1][n+1] in bottom up fashion. Note // that L[i][j] contains length of LCS of X[0..i-1] and Y[0..j-1] for (int i=0; i<=m; i++) { for (int j=0; j<=n; j++) { if (i == 0 || j == 0) L[i][j] = 0; else if (X.charAt(i-1) == Y.charAt(j-1)) L[i][j] = L[i-1][j-1] + 1; else L[i][j] = Math.max(L[i-1][j], L[i][j-1]); } } // Following code is used to print LCS int index = L[m][n]; int temp = index; // Create a character array to store the lcs string char[] lcs = new char[index+1]; lcs[index] = '\u0000'; // Set the terminating character // Start from the right-most-bottom-most…public class Soru32{ // Returns length of LCS for X[0..m-1], Y[0..n-1] static void lcs(String X, String Y, int m, int n) { int[][] L = new int[m+1][n+1]; // Following steps build L[m+1][n+1] in bottom up fashion. Note // that L[i][j] contains length of LCS of X[0..i-1] and Y[0..j-1] for (int i=0; i<=m; i++) { for (int j=0; j<=n; j++) { if (i == 0 || j == 0) L[i][j] = 0; else if (X.charAt(i-1) == Y.charAt(j-1)) L[i][j] = L[i-1][j-1] + 1; else L[i][j] = Math.max(L[i-1][j], L[i][j-1]); } } // Following code is used to print LCS int index = L[m][n]; int temp = index; // Create a character array to store the lcs string char[] lcs = new char[index+1]; lcs[index] = '\u0000'; // Set the terminating character // Start from the right-most-bottom-most…
- Write a program Calculator.java. Instead of using integers, use rationals, as shown in Figure .You will need to use the split method in the String class, introduced inSection10.10.3, Replacing and Splitting Strings, to retrieve the numerator stringand denominator string, and convert strings into integers using the Integer.parseIntmethod.Please help debug this: Debugging Exercise 4-3, Farrell, Joyce, Java Programming, 9th edition, Cengage Learning public class DebugBox { private int width; private int length; private int height; private FixDebugBox() { length = 1; width = 1; height = 1; } public DebugBox(int width, int length, int height) { width = width; length = length; height = height; } public void showData() { System.out.println("Width: " + width + " Length: " + length + " Height: " + height); } public double getVolume() { double vol = length - width - height; return vol; } }class B extends A {} is the correct way to implement an interface in Java. True or False?
- The following is in Java: public class MyClass { private int x; private double y; public static void setValues(int a, double b) { x = a; y = b; } } 1) What is the problem? 2) In a few sentences how can the issue be fixed?FOR JAVA, PLEASE WRITE THE CODE OF THIS QUESTION FOR JAVA Write a static method histogram() that takes an array a[ ] of int values and an integer M as arguments and returns an array of length M whose ith entry is the number of times the integer i appeared in the argument array. If the values in a[ ] are all between 0 and M–1, the sum of the values in the returned array should be equal to a.length.Write a java program with a method that reverses a string The method must accept one parameter of type String (string to reverse), and returns every second element from the end to the beginning. For example: String: thisisstringResult is: g i t s s h
- in a few sentences say: c++ uses Templates, but Java uses Generic classes which one is better or you will choose which one why?I have no idea how to do this problem Write a library of static methods that performs various geometric transforms on polygons. Mathematically, a polygon is defined by its sequence of vertices (x0, y 0), (x 1, y 1), (x 2, y 2), …. In Java, we will represent a polygon by storing the x– and y-coordinates of the vertices in two parallel arrays x[] and y[]. // Represents the polygon with vertices (0, 0), (1, 0), (1, 2), (0, 1). double x[] = { 0, 1, 1, 0 }; double y[] = { 0, 0, 2, 1 }; Three useful geometric transforms are scale, translate and rotate. Scale the coordinates of each vertex (x i, y i) by a factor α. x‘i = α xi y‘i = α yi Translate each vertex (x i, y i) by a given offset (dx, dy). x‘i = xi + dx y‘i = yi + dy Rotate each vertex (x i, y i) by θ degrees counterclockwise, around the origin. x‘i = xi cos θ – yi sin θ y‘i = yi cos θ + xi sin θ Write a two-dimensional transformation library by implementing the…please i have problem with run import java.util.*;public class Main{ public static void main(String args[]) { int[][] Arr=new int[2][3]; Random r=new Random(); for(int i=0;i<2;i++) { for(int j=0;j<3;j++) { Arr[i][j]=r.nextInt(100); } } System.out.println("Elements in the array:\n"); for(int i=0;i<2;i++) { for(int j=0;j<3;j++) { System.out.print(Arr[i][j]+","); } System.out.println(); } System.out.println("\nElements in the array after adding 8:\n"); for(int i=0;i<2;i++) { for(int j=0;j<3;j++) { Arr[i][j]+=5;…