What is the rate of thermal radiation emitted from a star with a radius of 4.11 x 109 m and a surface temperature of 3,222 K? Assume that the spherical surface behaves as a blackbody radiator.
Q: (b) What is the surface temperature of the star? 4274.3 X K (c) At what rate is energy emitted from…
A: b) The star’s surface temperature can be determined by Wein’s displacement law as, Here, T, b, and…
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A: Frequency f is related to wavelength λ is given by f=C/λ, where C= speed of light
Q: A blackbody at 200 K is emitting to surroundings. (a)- Calculate the wavelength at which the…
A: Solution: (a). Use the Wien displacement formula to find the wavelength corresponding to maximum…
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A: We are strictly following the data given in the question: Solar power per unit area = 1381.465…
Q: Calculate the temperature of a blackbody that peaks at a frequency of 7.5·108 MHz.
A: Given Fmax = 7.5 x 108 MHz = 7.5 x 108 x 106 Hz
Q: What wavelength (in nanometers) is the peak intensity of the light coming from a star whose surface…
A: Determine the wavelength of the light.
Q: A particular blackbody has a radiation spectrum that peaks at a wavelength of 660 nm. Part (a)…
A: Given, Wavelength = 660 nm We need to calculate, (a) Temperature =? (b) If temperature =4300K…
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Q: The radius of our sun is r = 6.96 × 108 m and its total power is 3.85 × 1026 W. The area of a sphere…
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A: Let the frequency be given by f and the temperature of the black-body is given by T. Let the average…
Q: The star Betelgeuse has surface temperature 3590 K and can be regarded as a blackbody. (a) Find the…
A: The temperature of the Betelguese is given as T=3590 K (a). According to Weins displacement law, the…
Q: The total power radiated per unit area from a blackbody is 78.0 MW/m2. Find (a) the temperature of…
A: Power per unit area, P = 78 MW/m2
Q: PART 1)photon emitted as a hydrogen atom under goes a transition from the n = 3 state to the n = 2…
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Q: Consider a black body of surface area 22.0 cm² and temperature 5700 K. (a) How much power does it…
A: Given that: - Surface area (A) of the black body: 22.0 cm² - Temperature (T) of the black body: 5700…
Q: Assuming that the Sun is a blackbody with a temperature of 6,000 K, at what wavelength does it…
A: Given data: Temperature of sun is, T=6000 K.
Q: The Earth is spherical in shape and can be considered to be a perfect black body radiator at a…
A: Given Data Temperature is given as T=58°C=(58+273) K=331 K Radius of the Earth is R=6360 km=6360…
Q: he filament of a light bulb has a surface area 64 mm2. The filament can be considered as a black…
A: Given data- surface area of filament (A)=64 m2 Temperature (T)=2500 K
Q: The filament of a light bulb has a surface area 64 mm2. The filament can be considered as a black…
A: We have been provided that- Surface area of the filament (A)=64 mm2 Temperature (T)=2500 K…
Q: (b) Suppose we can write the partition function of N inseparable gas particles as the one-particle…
A: (b) Given that Consider the partition function of N inseparable gas particle is given as ZN=Z1NN!…
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Q: Hydrogen H2 is a diatomic molecule composed of two hydrogen atoms. (Figure 1) is an energy diagram…
A: Given that: The velocity is v=19 km/s= 19×103 m/s The distance is x=0.05 nm The energy is…
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Q: The spectrum of light from a star is, to a good approximation, a blackbody spectrum. The red…
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Q: The temperature of the surface of Pluto is about T(K) = 40 K (TC = -230 °C). %3D According to Wien's…
A: Given data, The maximum wavelength is, λmax=72.5 μm The speed of the radiation is c=3×108 m/s The…
Q: The two nuclei in the carbon monoxide (CO) molecules are 0.1128 nm apart. The mass of the carbon…
A: The energy difference between the first excited state and the ground state can be calculated using…
Q: (A) Every square meter area facing the Sun, at the distance 1 AU from the Sun, receives radiant…
A: A) Given that:Prec=1.368 kW=1.368×103 WA=1 m2
Q: A particular star has a radius of 8.46 ✕ 108 m. The peak intensity of the radiation it emits is at a…
A: (Since it is a multipart question, the first three questions are done). Photon energy is the energy…
Q: Calculate the power radiated by a black body of surface area 20. 0 cm2 and temperature 6000 K
A: A black body is considered an ideal body capable of absorbing all the radiation that falls on it.…
Q: The Temperature of a blackbody increases from 200°C to 400° C. What is the change in the frequency…
A: Using the Wiens displacement law. λmT=constant=0.2898⇒λm1T1=λm2T2 Converting the wavelength into…
Q: The sun has a luminosity of 3.9 × 1026 W and an angular diameter of θ = 32 arc mins. Assume that the…
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Q: Suppose a star with radius 8.51 108 m has a peak wavelength of 689 nm in the spectrum of its…
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Q: The filament of a light bulb has a surface area 64 mm2. The filament can be considered as a black…
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Q: The light from the sun is found to have a maximum intensity near the wavelength of 470 nm. Assuming…
A: To find-Temperature of sun (T)=?Given-Wavelength (λ)=470 nm=470×10-9 mWien's constant (b)=2.898×10-3…
Q: What is the rate of thermal radiation emitted from a star with a radius of 2.310x 109mand a surface…
A: A blackbody is considered as an ideal physical body which will absorb and emit all the radiations…
Q: An X-ray photon with a wavelength of 0.999 nmnm strikes a surface. The emitted electron has a…
A: Given Wavelength = 0.999 nm Kinetic energy of electron = 990eV 1 eV = 1.602*10-19 J So energy of…
Q: What will be the energy associated with a blue photon (in Joules), if the frequency of the blue…
A: Given f=650 THz 1THz= 1012 Hzh=6.63×10-34 Jsor h=4.14 ×10-15 eVs
Q: 17.2 (a) Use the fact that f [2³/(e² - 1)] dz = π/15 to show that the total radiant energy emitted…
A: The total radiant energy emitted per unit area by a blackbody is given by the Stefan-Boltzmann law:…
Q: Vega is the fifth brightest star in the night sky. This bluish dwarf star has a radius of 0.810 x…
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Q: What temperature, in °C, is a blackbody whose emission spectrum peaks at 420 nm ? Express your…
A: Wein's law states thatPart (A) Peak wavelength=420 nm = 420×10-9 mPart (B) Peak wavelength=3.00…
[Surface Area of a sphere = 4πr2; Area of a circle = πr2 or (π/4)d2]
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