What is the solution of (x² + 2xy - 4y²)dx - (x² − 8xy – 4y²)dy =0 ? - - a. x² - 4y² = c(x-y) b. x² + 2y² = c(x+2y) c. x² + 2y² = c(x-2y) d. x² + 4y² = c(x+y)

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter13: Conic Sections
Section13.1: Circles
Problem 48PS
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What is the solution of (x² + 2xy − 4y²)dx − (x² − 8xy – 4y²)dy =0 ?
a. x² - 4y² = c(x-y)
b. x² +2y² = c(x+2y)
c. x² + 2y² = c(x-2y)
d. x² + 4y² = c(x+y)
Transcribed Image Text:What is the solution of (x² + 2xy − 4y²)dx − (x² − 8xy – 4y²)dy =0 ? a. x² - 4y² = c(x-y) b. x² +2y² = c(x+2y) c. x² + 2y² = c(x-2y) d. x² + 4y² = c(x+y)
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