What language is accepted by this PDA?a, alaab, a/Ab, b/bbc, b/Aa, Zo/aZob, Zo/bZoc, b/AA.Zo/Zob, a/A12939495O L = {a^n b^(n+m) c^m | n,m>0}O L= {a^n b^(m) c^(n+m) | n,m>0}O L= {a^(n+m) b^n c^m|n,m>0}O L= {a^m b^(n+m) c^m | n.m>0}

We are given a Push Down Automata (PDA) and we are asked what language is accepted by this PDA.…

What language is accepted by this PDA? a, a/aa b, a/A b, b/bb c, b/A a, Zo/aZo b, Zo/bZo 42 c, b/A b, a/A A,Z,/Z, 93 94 45 O L= {a^n b^(n+m) c^m n.m>0} OL= {a^n b^(m) c^(n+m) | n,m>0} O L= (a^(n+m) b^n c^m | n.m>0} O L= {a^m b^(n+m) c^m n.m>0}

What language is accepted by this PDA? a, a/aa b, a/A b, b/bb c, b/A a, Zo/aZo b, Zo/bZo 42 c, b/A b, a/A A,Z,/Z, 93 94 45 O L= {a^n b^(n+m) c^m n.m>0} OL= {a^n b^(m) c^(n+m) | n,m>0} O L= (a^(n+m) b^n c^m | n.m>0} O L= {a^m b^(n+m) c^m n.m>0}

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Parallel processing

The process of running two or more processors together is known as parallel processing. In parallel processing, a single process is divided into multiple parts, and each individual part is executed at the same time. It is used to handle various parts of a task at the same time. The main advantage of parallel processing is the reduction of the processing time of the program, where the processor in a system is the CPU. Hence, parallel processing can be performed by using multiple CPUs, and having more than one CPU creates a multi-processor. Another name of parallel processors is block processors. Here, the size of a block is the number of inputs that can be processed simultaneously in a single clock cycle.

Question

What language is accepted by this PDA?
a, alaa
b, a/A
b, b/bb
c, b/A
a, Zo/aZo
b, Zo/bZo
c, b/A
A.Zo/Zo
b, a/A
12
93
94
95
O L = {a^n b^(n+m) c^m | n,m>0}
O L= {a^n b^(m) c^(n+m) | n,m>0}
O L= {a^(n+m) b^n c^m|n,m>0}
O L= {a^m b^(n+m) c^m | n.m>0}

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